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+--- Thread: Ascii Tree Art (/thread-14702.html)
Ascii Tree Art - beepBoop123 - Dec-12-2018
Hi, I'm trying to create a function that will make the correct sized ascii Christmas tree art based on the size passed in. This is what I have so far
def get_festive(size):
Triangle = ""
for i in range (size+4):
Triangle += ("*"*((i*4)+1)).center(((size*4))," ")
Triangle += "\n"
return TriangleThis is what I need it to look like:get_festive(3)
*
*****
*********
*************
*****
*********
*************
*****************
*********
*************
*****************
********************* This is what I have so far:get_festive(3)
*
*****
*********
*************
*****************
*********************
*************************Any suggestions or if you know what to fix let me know - thank you!
RE: Ascii Tree Art - ichabod801 - Dec-13-2018
One thing is that you need to center based on the largest line you are going to print. In the case of your current code that would be (size + 4) * 4, not just size * 4.
Beyond that it's hard to say, because the general case is not clear. Do you have more detailed instructions for the assignment, or examples of what get_festive(2) and get_festive(4) should look like?
RE: Ascii Tree Art - beepBoop123 - Dec-13-2018
get_festive(2)
*
*****
*********
*************
*****
*********
*************
*****************get_festive(1)
*
*****
*********
*************here are the other ones (:
RE: Ascii Tree Art - ichabod801 - Dec-13-2018
You need two nested loops. Each tree is made of a number of trapezoids equal to it's size. Each trapezoid has four rows. That should tell you what the two loops you need are. The number of *'s at any level is a function of the sum of the two looping variables. Remember to center based on the largest number of *'s you will get.
RE: Ascii Tree Art - Gribouillis - Dec-13-2018
ichabod801 Wrote:You need two nested loops.I'm using only one loop
for n in range(4 * size):
...The divmod() function helps.
RE: Ascii Tree Art - ichabod801 - Dec-13-2018
Well, you could do it with no loops, but let's start him out with the two loop solution.