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+--- Thread: if-elif-else statement not executing (/thread-15132.html)
if-elif-else statement not executing - laila1a - Jan-05-2019
Hi everyone, I'm new to programming so sorry in advance if my mistake is a stupid one.
I am having trouble making my if-elif-else statement execute properly in my dice rolling simulator, it always defers to the statement for the else part, no matter the input. For example, if the user inputs 1 to play again, they will be told the input is not valid. Same thing if they input 2 in order to stop playing.
Here is my code:
from random import randint
def diceRollingSimulator():
dice = randint(1, 6)
print(dice)
diceRollingSimulator()
answer = input("Would you like to play again? (enter 1 for yes or 2 for no): ")
if answer == 1:
diceRollingSimulator()
elif answer == 2:
print("Thanks for playing!")
else:
print("Not a valid input!")
RE: if-elif-else statement not executing - buran - Jan-05-2019
input() will return str. In your if/elif conditions you compare str to int. so it's never True and else clause is executed.You can either convert
answer to int e.g. answer = int(input(...)) or alterntaively, compare answer to str, e.g. if answer == '1':
RE: if-elif-else statement not executing - stullis - Jan-05-2019
The input() function always returns a string. Because strings are not numbers, they cannot be compared. To fix this, you need to cast the input to a number type:
from random import randint
def diceRollingSimulator():
dice = randint(1, 6)
print(dice)
diceRollingSimulator()
answer = int(input("Would you like to play again? (enter 1 for yes or 2 for no): "))
if answer == 1:
diceRollingSimulator()
elif answer == 2:
print("Thanks for playing!")
else:
print("Not a valid input!")
RE: if-elif-else statement not executing - laila1a - Jan-05-2019
Thank you!
RE: if-elif-else statement not executing - buran - Jan-05-2019
answer = int(input("Would you like to play again? (enter 1 for yes or 2 for no): "))Note that it will raise an exception if input is not valid for conversion to int with base 10.