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Finding Row Number for Items in 2D array - fafzal - Jan-10-2019 Hi everyone. First post here because I'm completely stuck on my homework assignment. I don't have a strong coding background so any help is greatly appreciated. I have a set of 25 randomly generated numbers. The array is shaped 5 x 5. I need to be able to multiply the numbers in each row with it's row numbers. All numbers in row 1 x 1, all numbers in row 2 x 2 etc. Here is what I have and I'm not sure how to get the address (row number) for every item in the array: import random mu, stdev = 5, 5 random.seed(1) three = np.random.normal(mu, stdev, 25).reshape(5,5) for x in three: y = x * x.shape[0] print (x.shape[0]) RE: Finding Row Number for Items in 2D array - scidam - Jan-10-2019 No loops needed. Numpy can do all the work by itself: three = three * np.arange(three.shape[0])[:, np.newaxis] # 0-based numbering # or three = three * np.arange(1, three.shape[0] + 1)[:, np.newaxis] # 1-based numbering RE: Finding Row Number for Items in 2D array - fafzal - Jan-10-2019 (Jan-10-2019, 05:57 AM)scidam Wrote: No loops needed. Numpy can do all the work by itself:This works neatly but I'm sorry I should have mentioned that I'm asked to do this using indexing and looping.three = three * np.arange(three.shape[0])[:, np.newaxis] # 0-based numbering # or three = three * np.arange(1, three.shape[0] + 1)[:, np.newaxis] # 1-based numbering I was able to find a way and wanted to post back. Here's what worked Thanks for the help for i in range (0,5): three[i]=three[i]*(i+1) |