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+--- Thread: from 50 random numbers printing only the sqrt(...)==0 (/thread-15311.html)
from 50 random numbers printing only the sqrt(...)==0 - AFKManager - Jan-12-2019
Hey i need to write a program to school and im new to python so im trying different things.
I need to choose 50 random numbers from interval f.e. from 100 random numbers and do number**0.5 and i need it to output the whole numbers that are int after finishing = 25**0.5=5
i have this but honestly its bad af or idk
import random
def main():
for i in range(50):
list=random.randint(1,100)
a =[list]
for i in a:
if i**(0.5)==0:
print(i)I dont know what to do because we have like teacher that doesnt know it either so i dont know
RE: from 50 random numbers printing only the sqrt(...)==0 - ichabod801 - Jan-12-2019
Please use python and output tags when posting code and results. I put them in for you this time. Here are instructions for doing it yourself next time.
First, don't name a variable list. The word list has meaning in python, and if you use it as a variable name, you lose access to that, and so does other code that may depend on it.
On line 4, you assign a random number to list. Fifty times you do this, and every time you are writing over the last one you did. So at the end, list is just a random number, and the variable 'a' only has one number in it. You want to initialize the list, and then append to it in the loop:
numbers = []
for number in range(50):
numbers.append(random.randint(1, 100)