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+--- Thread: Copy List Structure (/thread-16929.html)
Copy List Structure - leoahum - Mar-20-2019
L1 = [[1,2,3],[4,2],[6,8,1],[4,3]]
L2 = [1,2,3,4,5,6,7,8,9,10]
L3 =[]
def ListStrcCopy(L1,L2):
L = []
for i in L1:
L.append (L2.pop(0))
return L
for i in L1:
L3.append(ListStrcCopy(i,L2))
print (L3)I'm trying to copy the list structure from L1 to L2. The new list is [[1, 2, 3], [4, 5], [6, 7, 8], [9, 10]]. The script above achieved the goal, but I'm seeking for a simpler way to do that.Thanks!
RE: Copy List Structure - ichabod801 - Mar-20-2019
Instead of taking the items off individually, you could take them off in slices:
L1 = [[1,2,3],[4,2],[6,8,1],[4,3]]
L2 = [1,2,3,4,5,6,7,8,9,10]
L3 =[]
start = 0
for sub in L1:
L3.append(L2[start:(start + len(sub))])
start += len(sub)
RE: Copy List Structure - leoahum - Mar-22-2019
(Mar-20-2019, 04:09 PM)ichabod801 Wrote: Instead of taking the items off individually, you could take them off in slices:
L1 = [[1,2,3],[4,2],[6,8,1],[4,3]] L2 = [1,2,3,4,5,6,7,8,9,10] L3 =[] start = 0 for sub in L1: L3.append(L2[start:(start + len(sub))]) start += len(sub)
Thanks a lot! I had that idea, but couldn't figure out how to do that in Python.