Comparing complicated arrays. - Printable Version

Comparing complicated arrays. - Printable Version

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Comparing complicated arrays. - kietrichards - Apr-12-2019

Hello. Do you have any idea how to compare this example two arrays? Here it's not visable. But nummber of columns in both arrays is the same, but number of items is different. So for example, zero in first row, column third corresponds to number in first row, third column etc. So I'd like to put corresponding numbers into subsets "0", "1" and "unknown". Maybe you have at least an idea on method. Thanks in advance :)

#Array1
COLUMNS_1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 1 0 0 0 0 1 0 1 1 0 0 1 1 0 0 0 0 1 0 1

#Array2
Trxxx HAEIAM texttex texxx texx rexx rr rxx texx text t 3.86 3.58 3.54 3.70 3.08 3.17 3.75 3.23 3.72 3.11 3.65 3.87 3.21 3.58 3.10 3.87 4.31 3.97 3.69 3.47 3.49 3.23 3.69 3.73 3.61 3.59 3.56 3.46 3.53 3.57 3.19 3.42 3.77 3.34 3.39 3.34 3.02 3.33 3.07 3.74 3.42 3.12 3.31 3.57 2.92 3.48 2.77 3.00 3.54 3.36 3.53 3.51 3.67 2.76 3.39 3.22 3.31 3.82 3.71 3.38 3.60 3.54

RE: Comparing complicated arrays. - Larz60+ - Apr-12-2019

Quote:So for example, zero in first row, column third

zero based, columns_1[3] is a 1, not 0, so assume you mean index 2 for column 3, correct?

>>> zz = '0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 0 0 1 1 0 0 0 0 1 0 1 1 0 0 1 1 0 0 0 0 1 0 1'
>>> columns_1 = zz.split()
>>> columns_1[3]
'1'
>>>

Hard to understand your goal. Please show example result

RE: Comparing complicated arrays. - kietrichards - Apr-12-2019

So it's difficult to explain how the file looks. I copied a part to editor and shared a link:

https://ibb.co/YNkXNB7

So an example output would be:

#unknown
3.22 3.31 3.82 3.71 3.38 3.60 3.54

#1
3.86 3.54 3.08 3.75 3.21 3.10 4.31 3.39 3.34 3.42 3.31 3.57 2.77 3.00

#the same for 0

RE: Comparing complicated arrays. - Larz60+ - Apr-12-2019

Ok, next question, what have you tried?
Please post code