charmap codec can't decode byte error with gzipped file in python

charmap codec can't decode byte error with gzipped file in python - Printable Version

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charmap codec can't decode byte error with gzipped file in python - bluethundr - Apr-29-2019

I am attempting to send an email that includes a file in gzip format as an attachment using python.

But I'm getting an error when I try to send the file. This is the exception I'm getting:

Exception:

'charmap' codec can't decode byte 0x90 in position 75: character maps to <undefined>

This is what I'm doing in my code:

    import gzip
    destination = 'path/to/file'
    to_addr = input("Enter the recipient's email address: ")
    from_addr = '[email protected]'
    subject = "Commpany AWS Billing Info "
    content = "email to the user about the file"
    msg = MIMEMultipart()
    msg['From'] = from_addr
    msg['To'] = to_addr
    msg['Subject'] = subject
    body = MIMEText(content, 'html')
    msg.attach(body)
    server = smtplib.SMTP('smtpout.us.companyworld.company.com', 25)
    filename = destination
    try:
        with open(filename, 'r') as f:
            part = MIMEApplication(f.read(), Name=basename(filename))
            part['Content-Disposition'] = 'attachment; filename="{}"'.format(basename(filename))
            msg.attach(part)
            server.send_message(msg, from_addr=from_addr, to_addrs=[to_addr])
        print("Email was sent to: %s" %  to_addr)
    except Exception as e:
        print("Exception: ", e)
        print("Email was not sent.")

The file I am trying to send was created in another function in these lines:

        import pandas
        read_sql = 'select * from somedb'
        mydb = mysql.connector.connect(user='x', password='x',host='x',database='aws_bill')
        results = pandas.read_sql_query(read_sql, mydb)
        results.to_csv(destination, index=False, encoding='utf8', compression='gzip')

How can I correct this problem and send the attachment?

RE: charmap codec can't decode byte error with gzipped file in python - snippsat - Apr-30-2019

You should post all Traceback because there is also line number of error.
Also all email imports should be posted.

Try line 11:

body = MIMEText(content, 'html', 'utf-8')

Line 16:

with open(filename, 'r', encoding='utf-8') as f:

RE: charmap codec can't decode byte error with gzipped file in python - bluethundr - Apr-30-2019

(Apr-30-2019, 04:58 AM)snippsat Wrote: You should post all Traceback because there is also line number of error.
Also all email imports should be posted.

Try line 11:
body = MIMEText(content, 'html', 'utf-8') 
Line 16:
with open(filename, 'r', encoding='utf-8') as f:

OK thanks! I will do that next time, and note it going forward that I should post full stack traces. The problem turned out to be that the gzipped file is a binary. So I need to use this option to send it:

with open(filename, 'rb') as f: