Getting a "Cannot be Opened"" error Message

Getting a "Cannot be Opened"" error Message - Printable Version

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Getting a "Cannot be Opened"" error Message - valerydolce - Feb-09-2017

Hi Folks,
I'm having a "Cannot opened" error message even though i have the file in my directory. below is my code which consist of reading a file and determining the average game won.

Quote:

#! /usr/bin/python3
def team_average(filename):
        numberOfGames = 0
        soxWins = 0
        try:
                file = open(filename, 'r')
                for line in file:
                        numberOfGames += 1
                        game = line.split()
                        scores = game[1]
                        scores_list = scores.split('-')
                        for score in scores_list:
                                if int(score[0]) - int(score[1]) > 0:
                                        soxWins += 1
                average_win = int(s0xWins/numberOfGames) * 100
        except:
                print (filename, "Cannot be opened")

team_average('xxxxx')
print(team_average('red_sox.txt'))

Quote:# This is my output (which is not what i was expecting )

xxxxx Cannot be opened
red_sox.txt Cannot be opened
None

Please what did i get wrong ?
Best,
valerydolce

Below is the content of the "red_sox.txt" file

2011-07-02 Red Sox @ Astros Win 7-5
2011-07-03 Red Sox @ Astros Win 2-1
2011-07-04 Red Sox vs Blue Jays Loss 7-9
2011-07-05 Red Sox vs Blue Jays Win 3-2
2011-07-06 Red Sox vs Blue Jays Win 6-4
2011-07-07 Red Sox vs Orioles Win 10-4
2011-07-08 Red Sox vs Orioles Win 10-3
2011-07-09 Red Sox vs Orioles Win 4-0
2011-07-10 Red Sox vs Orioles Win 8-6
2011-07-15 Red Sox @ Rays Loss 6-9
2011-07-16 Red Sox @ Rays Win 9-5
2011-07-17 Red Sox @ Rays Win 1-0
2011-07-18 Red Sox @ Orioles Win 15-10
2011-07-19 Red Sox @ Orioles Loss 2-6
2011-07-20 Red Sox @ Orioles Win 4-0
2011-07-22 Red Sox vs Mariners Win 7-4
2011-07-23 Red Sox vs Mariners Win 3-1
2011-07-24 Red Sox vs Mariners Win 12-8
2011-07-25 Red Sox vs Royals Loss 1-3
2011-07-26 Red Sox vs Royals Win 13-9
2011-07-27 Red Sox vs Royals Win 12-5
2011-07-28 Red Sox vs Royals Loss 3-4
2011-07-29 Red Sox @ White Sox Loss 1-3
2011-07-30 Red Sox @ White Sox Win 10-2
2011-07-31 Red Sox @ White Sox Win 5-3

RE: Getting a "Cannot be Opened"" error Message - Larz60+ - Feb-09-2017

what OS?
What are the file permissions?
Shouldn't matter because if you can list it, you should be able to list it.

Try the following.
add

import os
...
print('Current working directory: {}'.format(os.getcwd())

RE: Getting a "Cannot be Opened"" error Message - buran - Feb-09-2017

This is example how not to implement try/except - you catch all exceptions and provide a message that's not relevant.

you have s0xWins note that second character is zero, not o on line

average_win = int(s0xWins/numberOfGames) * 100

So your actual error is that s0xWins is used before assignment.

You should avoid using such catch-all exception clause, especially when you don't pass on the actual error description.

RE: Getting a "Cannot be Opened"" error Message - valerydolce - Feb-09-2017

It's on a linux host that i access remotely.
below are the permissions

Quote:total 3
-rwxr-xr-x 1 psimo it117-1G 602 Feb 9 05:57 hw2.py
-rw-r--r-- 1 psimo it117-1G 1214 Feb 3 21:07 red_sox.txt

RE: Getting a "Cannot be Opened"" error Message - Ofnuts - Feb-09-2017

(Feb-09-2017, 11:26 AM)valerydolce Wrote: It's on a linux host that i access remotely.
below are the permissions

Quote:total 3
-rwxr-xr-x 1 psimo it117-1G 602 Feb 9 05:57 hw2.py
-rw-r--r-- 1 psimo it117-1G 1214 Feb 3 21:07 red_sox.txt

This is irrelevant. See buran's answer. Your try/except is catching all errors, and the code wrongly assumes that they can only mean that the file cannot be opened. In that case the exception comes from an error in your code... You should only be catching exceptions of type IOError, so that errors from your code are duly reported.

RE: Getting a "Cannot be Opened"" error Message - Larz60+ - Feb-09-2017

buran got it right, the error causes an exception so the code doesn't complete

RE: Getting a "Cannot be Opened"" error Message - valerydolce - Feb-09-2017

Buran/oFnuts,
Per your advise, I changed the code as shown below and i got a bunch of error

def team_average(filename):
        numberOfGames = 0
        soxWins = 0
        try:
                file = open(filename, 'r')
        except:
                print (filename, "Cannot be opened")
        else:
                for line in file:
                        numberOfGames += 1
                        game = line.split()
                        scores = game[1]
                        scores_list = scores.split('-')
                        for score in scores_list:
                                if (int(score[0]) - int(score[1]) > 0:
                                        soxWins += 1
                average_win = int(soxWins/numberOfGames) * 100

team_average('xxxxxx')
print(team_average('red_sox.txt'))

and below is the error i got :

Quote:Traceback (most recent call last):
File "./hw2.py", line 25, in <module>
print(team_average('red_sox.txt'))
File "./hw2.py", line 20, in team_average
if int(score[0]) - int(score[1]) > 0:
ValueError: invalid literal for int() with base 10: 'R'

RE: Getting a "Cannot be Opened"" error Message - Larz60+ - Feb-09-2017

You need a closing parenthesis:

                if (int(score[0]) - int(score[1])) > 0:

also, can't do this:

  try:
      file = open(filename, 'r')
  except:
      print (filename, "Cannot be opened")
  else:

and finally you're indentation seems all messed up

I take the last bit back, you can have an else clause - but it's not being used properly here

RE: Getting a "Cannot be Opened"" error Message - valerydolce - Feb-09-2017

I did but it still returned the same error !

Regarding the indentation, i'm using the tabulation key instead of space.

RE: Getting a "Cannot be Opened"" error Message - Larz60+ - Feb-09-2017

def team_average(filename):
    numberOfGames = 0
    soxWins = 0
    try:
        with open(filename, 'r') as file:
            for line in file:
                numberOfGames += 1
                game = line.split()
                scores = game[1]
                scores_list = scores.split('-')
                print('scores_list: {}'.format(scores_list))
                for score in scores_list:
                    if (int(score[0]) - int(score[1])) > 0:
                        soxWins += 1
                    average_win = int(soxWins / numberOfGames) * 100

                    team_average('xxxxxx')
                    print(team_average('red_sox.txt'))
    except:
        print(filename, "Cannot be opened")

team_average('red_sox.txt')

This is why print statements are so useful

results:

Output:C:\Python35\python.exe M:/python/e-h/f/forum/misc4.py
scores_list: ['Red']
red_sox.txt Cannot be opened

because score has 'Red' in it, it causes an exception (but not a file exception)
The exception is caught, but displays the wrong message (becuase not being qualified)

adding one more print statement makes the problem very clear:

def team_average(filename):
    numberOfGames = 0
    soxWins = 0
    try:
        with open(filename, 'r') as file:
            for line in file:
                numberOfGames += 1
                game = line.split()
                print('game: {}'.format(game))
                scores = game[1]
                scores_list = scores.split('-')
                print('scores_list: {}'.format(scores_list))
                for score in scores_list:
                    if (int(score[0]) - int(score[1])) > 0:
                        soxWins += 1
                    average_win = int(soxWins / numberOfGames) * 100

                    team_average('xxxxxx')
                    print(team_average('red_sox.txt'))
    except:
        print(filename, "Cannot be opened")

if __name__ == '__main__':
    team_average('red_sox.txt')

result:

Output:game: ['2011-07-02', 'Red', 'Sox', '@', 'Astros', 'Win', '7-5']
scores_list: ['Red']
red_sox.txt Cannot be opened