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+--- Thread: calculation with list in list (/thread-20393.html)
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calculation with list in list - gianniskampanakis - Aug-08-2019
hello. with this code i can calculate 1 + 2 + 3 = 6
l = [1,2,3,]
def suml(l):
s= 0
for i in l:
s = s + i
return s but what can i do if i want to calculate this list ( 1 + 2 +3 +( 1 + 2) = 9)
l = [1,2,3,[1,2]]
RE: calculation with list in list - ndc85430 - Aug-08-2019
What have you thought about, or tried?
RE: calculation with list in list - gianniskampanakis - Aug-08-2019
Somehow I have to use the def inside the def but I cant solve it . Or call the def repeatedly
RE: calculation with list in list - wavic - Aug-08-2019
You can try to flatten the nested lists first. There is a topic here about that.
RE: calculation with list in list - gianniskampanakis - Aug-08-2019
Well I need the code to work for both lists. It has to calculate every list that you can give .
RE: calculation with list in list - Yoriz - Aug-08-2019
(Aug-08-2019, 06:43 PM)gianniskampanakis Wrote: Somehow I have to use the def inside the def but I cant solve it . Or call the def repeatedly
Do you have to use Recursion ?
RE: calculation with list in list - gianniskampanakis - Aug-08-2019
No recursion is not needed. I study this exercise in order to give exams at university. Theoretically we have not learn yet recursion
The help note says: Write a sumL function that will calculate the sum of the elements of a list of numbers and call this function repeatedly.]
RE: calculation with list in list - cvsae - Aug-08-2019
Γεια σου γιαννη
l = [1,2,3,[1,2]]
def suml(l, s=0):
for i in l:
if type(i) == int:
s +=i
else:
return suml(i, s)
return sl = [1,2,3,[1,2]]
def suml(l):
s = 0
for i in l:
if type(i) == int:
s +=i
else:
for t in i:
s +=t
return s
RE: calculation with list in list - wavic - Aug-09-2019
This looks like recursion
RE: calculation with list in list - gianniskampanakis - Aug-09-2019
Σε ευχαριστώ το type(i) εκτός από int τι τιμες μπορεί να πάρει στην περίπτωση μας ;