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codebreaker exercise visualsteps - ivobrugman - Aug-10-2019 HI, Just starting out with python. Throught my book, a real basic book from visual steps I came to make below code. I think I understand all the working but one thing potentially puzzles me. I use this: for x in range(0,4): a few times. Now I understand what the loop does and that is is nested further down the code but, how does the interpreter understand that x comes from the number range which was initially put in under the variable "code". Even thinking about the indentation does not explain it to me fully. Anybody who can explain in baby logic :-) how python interpreter knows that x is processing the numbers given in the variable code (assuming I have that right). Any help appreciated. Thanks, Ivo import random import sys while True: # invoer code door de speler code = input("geef je code van 4 cijfers op (stop met 9999):") # controleer op cijfers only if code.isdigit(): #stop met het spel if int(code) == 9999: sys.exit() # controleren op 4 cijfers if len(code) == 4: # controleer dat de cijfers < 1 of > 6 fout=0 for x in range(0,4): if int(code[x]) < 1 or int(code[x]) > 6: fout=1 if fout == 0: # controleer of all getallen verschillen zijn gelijk=0 for x in range(0,4): for y in range(0,4): if x != y and code[x] == code[y]: gelijk=1 if gelijk == 0: break else: print ("twee of meer cijfers zijn hetzelfde") else: print("cijfers mogen niet lager dan 1 of hoger dan 6 zijn") else: print("er zijn te weinig of te veel cijfers") else: print("er staan letters in") print("all is well") RE: codebreaker exercise visualsteps - perfringo - Aug-11-2019 I have trouble understanding the question. However, I suggest to type into interactive interpreter: >>> help('for') The "for" statement ******************* The "for" statement is used to iterate over the elements of a sequence (such as a string, tuple or list) or other iterable object: for_stmt ::= "for" target_list "in" expression_list ":" suite ["else" ":" suite] The expression list is evaluated once; it should yield an iterable object. An iterator is created for the result of the "expression_list". The suite is then executed once for each item provided by the iterator, in the order returned by the iterator. Each item in turn is assigned to the target list using the standard rules for assignments (see Assignment statements), and then the suite is executed. When the items are exhausted (which is immediately when the sequence is empty or an iterator raises a "StopIteration" exception), the suite in the "else" clause, if present, is executed, and the loop terminates. A "break" statement executed in the first suite terminates the loop without executing the "else" clause’s suite. A "continue" statement executed in the first suite skips the rest of the suite and continues with the next item, or with the "else" clause if there is no next item. The for-loop makes assignments to the variables(s) in the target list. This overwrites all previous assignments to those variables including those made in the suite of the for-loop: for i in range(10): print(i) i = 5 # this will not affect the for-loop # because i will be overwritten with the next # index in the range Names in the target list are not deleted when the loop is finished, but if the sequence is empty, they will not have been assigned to at all by the loop. Hint: the built-in function "range()" returns an iterator of integers suitable to emulate the effect of Pascal’s "for i := a to b do"; e.g., "list(range(3))" returns the list "[0, 1, 2]". Note: There is a subtlety when the sequence is being modified by the loop (this can only occur for mutable sequences, e.g. lists). An internal counter is used to keep track of which item is used next, and this is incremented on each iteration. When this counter has reached the length of the sequence the loop terminates. This means that if the suite deletes the current (or a previous) item from the sequence, the next item will be skipped (since it gets the index of the current item which has already been treated). Likewise, if the suite inserts an item in the sequence before the current item, the current item will be treated again the next time through the loop. This can lead to nasty bugs that can be avoided by making a temporary copy using a slice of the whole sequence, e.g., for x in a[:]: if x < 0: a.remove(x) Related help topics: break, continue, while (END) RE: codebreaker exercise visualsteps - ivobrugman - Aug-11-2019 Thanks for the answer. My question is related to e.g. line 16 where x is used after "for". how does x know that it deals with the input given earlier in the "code" variable? (line 16 for your reference: for x in range(0,4):. I just do not understand how from the code line 16 knows this is about the input given in line 5. What if for instance when line 6 had a variable declared called code_2 or something like that. I miss a fundamental understanding is my feeling, despite the fact I know what it does, I just do not get how it does it. RE: codebreaker exercise visualsteps - ThomasL - Aug-11-2019 In the for-loops x doesn´t know anything :-) x is used as an index to address single items in the variable code which is a string. If you enter 4 digits the input() functions returns a string e.g. '1234'. Each character in the string can be accessed by using brackets e.g. code[0] is '1', code[1] is '2' etc. range(0,4) is an iterator function that assigns the variable x in the for-loop the values 0, 1, 2, 3 after another. If the start is 0, that value can be omitted, so range(4) does the same. But! In Python you can iterate directly over the contents of a string. for character in code: if int(character) < 1 or int(character) > 6: fout = 1is the pythonic way to do that verification. I refactored your code a little bit to give you some hints how things can be done. import random def main(): while True: # invoer code door de speler code = input("geef je code van 4 cijfers op (stop met 9999):") if code == '9999': break # controleer op cijfers only if code.isdigit(): # controleren op 4 cijfers if len(code) == 4: # controleer dat de cijfers < 1 of > 6 fout = False for cijfer in code: fout = cijfer in '0789' or fout if not fout: # controleer of all getallen verschillen zijn gelijk = False for x in range(4): for y in range(x+1, 4): gelijk = code[x] == code[y] or gelijk if not gelijk: print("your code meets all conditions") break else: print("twee of meer cijfers zijn hetzelfde") else: print("cijfers mogen niet lager dan 1 of hoger dan 6 zijn") else: print("er zijn te weinig of te veel cijfers") else: print("er staan letters in") print("all is well") if __name__ == '__main__': main() RE: codebreaker exercise visualsteps - ivobrugman - Aug-11-2019 Thanks, I understand. The fact that the loop is indented under de variable code links it to that variable, right? Thanks very much for taking the time to refactor, although...I will first (have to..)finish my basics and then get to the pythonic way. |