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+--- Thread: How to count and order numbers in a list (/thread-20598.html)
How to count and order numbers in a list - rachyioli - Aug-21-2019
Hi guys, I have a list of random numbers and I want to know how many times each number occurs on the list ; I want them ordered by the ones that occurred the most first.
This is my program :
lex=(1,2,3,4,5,6,1,2,3,3,3) x=0 for i in range(7): print(x," appeared ", lex.count(i)) x+=1and this is what I get :
Output:0 is 0
1 is 2
2 is 2
3 is 4
4 is 1
5 is 1
6 is 1is there a way I can use two functions at the same time in this loop.
thanks
RE: How to count and order numbers in a list - buran - Aug-21-2019
https://docs.python.org/3.7/library/collections.html#collections.Counter
>>> from collections import Counter
>>> spam = Counter((1,2,3,4,5,6,1,2,3,3,3))
>>> spam
Counter({3: 4, 1: 2, 2: 2, 4: 1, 5: 1, 6: 1})
>>>
RE: How to count and order numbers in a list - perfringo - Aug-21-2019
(Aug-21-2019, 10:22 AM)rachyioli Wrote: what I need now is to order them from the ones that happened the most in the list
You can extend solution provided by buran with .most_common method. If you want regular dict you can convert:
>>> spam.most_common(len(spam.keys()))
[(3, 4), (1, 2), (2, 2), (4, 1), (5, 1), (6, 1)]
>>> dict(spam.most_common(len(spam.keys())))
{3: 4, 1: 2, 2: 2, 4: 1, 5: 1, 6: 1}