if condition inside try / except -- how to?? - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: if condition inside try / except -- how to?? (/thread-21515.html) |
if condition inside try / except -- how to?? - ridgerunnersjw - Oct-02-2019 Good afternoon... Can someone please show me what I am missing. Basically I want to take an argument in and check if it exists within a tuple of valid arguments. If it does GREAT, if not raise an error that tells the user to try again..... _SCOPE_VARIABLES = ('open', 'read', 'write', 'query', 'close') class command: def __init__(self, command, scope = 'NONE', **kwargs): self.command = command self.scope = scope try: self.scope in _SCOPE_VARIABLES except: print ('Try again') Thanks RE: if condition inside try / except -- how to?? - micseydel - Oct-02-2019 It sounds like you want to throw (raise) an exception, not catch (try/except) one. Just have an if block based on your condition and raise an exception from within the block. By the way, it's weird that you have a default argument for scope which would result in an exception. It would probably be better to just require clients provide their own argument. |