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Max number of three - RavCOder - Oct-09-2019 Hi, In this function that I defined, it does not return to the maximum number of three, but return None. I used * args to see how it worked and I saw what it took for when there are many topics to put and I used max to set the maximum value. I think the problem is just * args and I wanted to know if there is a way to keep * args without adding arguments. This exercise took it from the Github repository "46 Simple Python Exercises" and this is the exercise: Quote:Define a function max_of_three() that takes three numbers as arguments and returns the largest of them. def max_of_three(*args): print(max(args)) if __name__ == "__main__": x = int(input()) y = int(input()) z = int(input()) print("The largest number is:",max_of_three(x,y,z))Regards, RavCoder RE: Max number of three - perfringo - Oct-09-2019 If you are not returning (or yield) anything from function it returns None. As you are not returning anything from max_of_three you get None. As assignment states - you should return maximum of three, so return max(args) should be in compliance with assignment.
RE: Max number of three - buran - Oct-09-2019 We don't see the actual assignment, but I really doubt they expect you to just wrap the built-in max() function
RE: Max number of three - RavCOder - Oct-09-2019 (Oct-09-2019, 07:49 AM)buran Wrote: We don't see the actual assignment, but I really doubt they expect you to just wrap the built-in I know you don't have to use max (), but I used it because I wanted to see how it worked. (Oct-09-2019, 07:35 AM)perfringo Wrote: If you are not returning (or yield) anything from function it returns None. As you are not returning anything from max_of_three you get None. As assignment states - you should return maximum of three, so Thanks it works now!! |