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+--- Thread: help with a call (/thread-22712.html)
help with a call - PyPy - Nov-23-2019
hi all,
I have a class which has a method which sort data in it. I need to create another method to check if data object I am dealing with is sorted or not. When I declare data object first it's not sorted. For checking whether this is sorted or not what I am doing is:
1) Create another data object and assigning original data object in it
2) Now sorting this new data object
3) Comparing newly created and sorted data object with original one
Problem I have is it's showing sorted as when I create a new data object and assign value of existing one in it and then sort this one, it' sorting original one also
def isOrdered(self):
sortedDeck=self.deck
sortedDeck.sort()
for i in range(0, len(self.deck)):
print(self.deck[i],sortedDeck[i])Any idea why it would be happening?
RE: help with a call - Larz60+ - Nov-23-2019
I haven't tested this, but it should work:
def is_ordered(self):
deck = self.deck
return all(deck[n] <= deck[n+1] for n in range(len(deck)-1))
RE: help with a call - Gribouillis - Nov-24-2019
A variation that only supposes that
self.deck is iterablefrom itertools import tee
def is_ordered(self):
t = tee(self.deck)
next(t[1], None)
return all(a <= b for a, b in zip(*t))
RE: help with a call - PyPy - Nov-24-2019
Thanks everyone for the suggestion.