Continuing code after exception - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: Continuing code after exception (/thread-23173.html) |
Continuing code after exception - palladium - Dec-14-2019 I have a module that takes several inputs from the end user, does some basic checking before getting called by another module to do some calculations. Here is some of the code: def smoking(): p = [] a = int(input("Are you a smoker? 0 = no, 1 = yes " )) p.append(a) while p[0] not in range (0,2): p.clear() b = int(input("Please enter 0 or 1 only. ")) p.append(b) return p[0] def diabetes(): p = [] a = int(input("Are you a diabetic? 0 = no 1 = yes " )) p.append(a) while p[0] not in range (0,2): p.clear() b = int(input("Please enter 0 or 1 only. ")) p.append(b) return p[0] try: smoking = smoking() diabetes = diabetes() except ValueError: print("Please enter numbers only")When the code is run and an exception is encountered (e.g. if I enter p instead of 0 or 1) the console prints "Please enter numbers only" as intended, but the code ends. Is there a way to get the code to loop if I enter a string, just like how if I enter a number outside 0 or 1? Thanks. RE: Continuing code after exception - ichabod801 - Dec-14-2019 We have a whole tutorial on this: Validating User Input |