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+--- Thread: It does truncatte where i would ... (/thread-23406.html)
It does truncatte where i would ... - AyUniz - Dec-28-2019
Hello !
I tried to do something that truncatte a list of strings but i doesn't truncate where i would to.
I show you what i would like:
(https://prnt.sc/qgww3f)
In the red rectangle is the thing i'd like to delete, but here what i have:
(https://prnt.sc/qgwwui)
How can I delete those ":" please ?
Here is the code:
import re
i = 0
fileString = input("Nom du fichier qui doit etre clean: ")
fileString = fileString.translate({ord('"'): None})
file = open(fileString, "r+")
logs = []
for line in file:
if i < 4:
i += 1
else:
logs.append(line[line.find(":"):])
file.seek(0)
file.truncate()
file.writelines(logs)
file.close()Thank you for answering :) ♥
RE: It does truncatte where i would ... - perfringo - Dec-28-2019
I don’t understand what and why this code does. But it seems to me that the way rows are structured enables simple approach to get needed part of string:
>>> s = “0xc624 (4): 1842” >>> s.rsplit(maxsplit=1)[1] 1842
RE: It does truncatte where i would ... - AyUniz - Dec-28-2019
(Dec-28-2019, 09:45 PM)perfringo Wrote: I don’t understand what and why this code does. But it seems to me that the way rows are structured enables simple approach to get needed part of string:
>>> s = “0xc624 (4): 1842” >>> s.rsplit(maxsplit=1)[1] 1842
I just would like the start of the strings to be removed until "(x):"
And sometimes, there is others things like "0x4562"
RE: It does truncatte where i would ... - perfringo - Dec-29-2019
From sample data I observe that needed part of the string is after first space from right. If so to the whole dataset then rsplit is obvious choice.