[Tkinter] Input box - Printable Version

[Tkinter] Input box - Printable Version

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Input box - Jpen10 - Dec-29-2019

I'm not very good at programming with tkinter and kivy. To set on the old Basic, Q basic, GWBasic and VBasic for Excel and MSAccess. I've tried numerous times to make a input box for the 11 digit UPC code. I now enter a "string" before the program runs on line 9. And the "while" works when I run the code without tkinter. When I add a input box I get a "nonsubscrptible error at the" For" statements. So I gave up. I've used this same code (with modifications) for quite a few years with Access and Excel. Not important, but would like to know how to solve the problems that arise. When the code runs I do get the correct output. Received some excellent help on this forum for the "join" statements. Thank you for any help.

# Computes last (12th) number of an 11 digit UPC
"""completeUPC.py"""
import sys
import os
from tkinter import *
import tkinter as tk
root = tk.Tk()

UPCNUM='19132910212'
odd=0
even=0
#while UPCNUM not in range(0,9) and len(UPCNUM) != 11:
#Add odd
for i in range(0,11,2):
	odd1=int(UPCNUM[i])
	odd=odd+odd1
# multiply odd by 3
odd=odd*3

#Add even
for i in range(1,11,2):
	even2=int(UPCNUM[i])
	even=even+even2

#Determine last number
lastnum=odd+even
lastnum=lastnum%10
lastnum=10 - lastnum
if lastnum == 10:
		lastnum  = 0
	
#12 digit UPC	
finalnumber=UPCNUM + str(lastnum)

#configure font code
s1 = finalnumber
s2 = 'PQRSTUVWXY'
s3 = '0123456789'
s4 = '@ABCDEFGHI'
s5='`abcdefghi'
first_str=""
last_str=""
pre_str=""
final_str = ""
divdr=chr(112)
pre_str =pre_str.join(s2[int(ch)] for ch in s1[0])
first_str=first_str.join(s3[int(ch)] for ch in s1[1:6])
last_str=last_str.join(s4[int(ch)] for ch in s1[6:11])
final_str = final_str.join(s5[int(ch)] for ch in s1[11])
upc_font=pre_str+first_str+divdr+last_str+final_str

#Copies to clipboard
r = Tk()
r.withdraw()
r.clipboard_clear()
r.clipboard_append(upc_font)
r.update() # now it stays on the clipboard after the window is closed
r.destroy()

#Produces label
tk.Label(root,
		 text=upc_font,
		 relief=RAISED,
		 borderwidth=10,
		 fg = "red",
		 bg = "white",
		 font = "UPCARev 16").pack()
		 
#Quit button
Button(root,
	text="Quit",
	fg="black",
	bg="green",
	font="helvetica 16",
	command=root.destroy).pack()
		 	
		  
root.mainloop()

RE: Input box - woooee - Dec-29-2019

#while UPCNUM not in range(0,9)

UPCNUM is never going to be in range(0. 9) because it is an 11 digit number being compared to a one digit number. You might want to use isdigit().

RE: Input box - Jpen10 - Dec-29-2019

The range 0 to 9 is to limit input to numbers and 11 digits. Since it is a string I have it as a comment. If I use =input () I get AN EOF Error. If I trap for the error I get the nontsubscritable error.

RE: Input box - woooee - Dec-30-2019

How do you expect help?

Quote:I now enter a "string" before the program runs on line 9

You do not get input anywhere in this code.

Quote:And the "while" works when I run the code without tkinter

There is no wile statement in the code you posted.

Quote:When I add a input box I get a "nonsubscrptible error at the" For" statement

Show the code. You are obviously doing it wrong.

Quote:I've used this same code (with modifications) for quite a few years with Access and Excel.

Don't care. They are completely different programming languages.

RE: Input box - Jpen10 - Dec-30-2019

I realize there is no input. That is the problem. The "while" on line 12 is commented out so the code runs. As of now, I enter the string on line 9. I would like a imput box to enter the 11 digits. Then run the code that follows, starting with the "for" statement on line 14 through line 50 and give the output of line 62.

RE: Input box - joe_momma - Dec-31-2019

try if:

if UPCNUM not in range(0,9) and len(UPCNUM) != 11:
    print('it failed to comply with my standards')

let the mainloop be the while statement- meaning it will always be waiting for a new input or user interaction. You have initialized Tk twice you can remove the second-

root.clipboard_clear()
root.clipboard_append(upc_font)
root.update()

Your terminology is confusing in the title you have input box but just a label and a button, if you want good answers work on the questions
sorry I final figured out what you're asking guizero is great for people starting...
you can find the info here: documentation
an example here

from guizero import App, TextBox, Text, PushButton
def calculate_upc():
    """Insert your code here"""
    text= 'your entry {}'.format(input_box.value)
    print(text)
app = App(layout='auto')
label= Text(app, text='Enter UPC', align='left')
input_box = TextBox(app,align='right',width='fill')
btn= PushButton(app, text='Submit', command=calculate_upc, align='bottom')            
app.display()

RE: Input box - Jpen10 - Jan-01-2020

Still can't get the 11 digits to run in the code. If I add a string of 11 numbers in line 23;"UPCNUM='96325932563' it works fine. And the 11 digits show If I enter 11 in the input box and press the "UPC number. "When I run the code with "UPCNUM=get11_digit" it gives me a "not iterable line 26." And if I code line 23 as "UPCNUM=get11_digit" it says get11_digit is not defined.

# Last (12th) number of an 11 digit UPC
"""comp_final_1_12020.py"""
import tkinter as tk
root= tk.Tk()

def get11_digit ():  
    x1 = entry1.get()
    label1 = tk.Label(root, text= x1)
    canvas1.create_window(200, 230, window=label1)

canvas1 = tk.Canvas(root, width = 400, height = 400)
canvas1.pack()

entry1 = tk.Entry (root) 
canvas1.create_window(200, 140, window=entry1)

button1 = tk.Button(text='UPC Number', command=get11_digit)
canvas1.create_window(200, 180, window=button1)

odd=0
even=0
n=2
UPCNUM=get11_digit
#Add odd

for i,x in enumerate(UPCNUM):
	if i % n == 0:
		odd=odd+int(x)
		
odd=odd*3

#Add even
for i,x in enumerate(UPCNUM):
	if i % n == 1:
		even=even+int(x)

#Determine last number
lastnum=odd+even
lastnum=lastnum%10
lastnum=10 - lastnum
if lastnum == 10:
		lastnum  = 0
	
#12 digit UPC	
UPC_12=UPCNUM + str(lastnum)

#configure font code
s1 = UPC_12
s2 = 'PQRSTUVWXY'
s3 = '0123456789'
s4 = '@ABCDEFGHI'
s5='`abcdefghi'
first_str=""
last_str=""
pre_str=""
final_str = ""
divdr=chr(112)
pre_str =pre_str.join(s2[int(ch)] for ch in s1[0])
first_str=first_str.join(s3[int(ch)] for ch in s1[1:6])
last_str=last_str.join(s4[int(ch)] for ch in s1[6:11])
final_str = final_str.join(s5[int(ch)] for ch in s1[11])
upc_font=pre_str+first_str+divdr+last_str+final_str

label2 = tk.Label(root,text=upc_font)
canvas1.create_window(200,300, window=label2)
	 
button2 = tk.Button(text='Quit', command=root.quit)
canvas1.create_window(200,350,window=button2)

root.mainloop()

RE: Input box - Jpen10 - Jan-27-2020

Finally! After several days of frustrarion and trials, I finally got it to work. Not real proud of the code, however, it works.