Keeps showing prevuios inputs - Printable Version

Keeps showing prevuios inputs - Printable Version

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Keeps showing prevuios inputs - _ShevaKadu - Jan-05-2020

python

Hello!
I'm making a Python module to get customised pop-ups.
But when I save the output to a variable (var = func(a, b)), and then print it out, it prints out the input I entered previously! Why?
Codes:
msg_return(return value) function code:

def msg_return(returnvalue):
    global msg_outputvalue
    msg_outputvalue = returnvalue
    msg_outputvalue = returnvalue

entry1 code:

    elif msgbox_widgets == 'input':
        msgbox_entry1 = Entry(msgbox_window, width=32, font=('Futura', 16))
        msgbox_entry1.place(x=145, y=82)
        msgbox_button1 = Button(msgbox_window, text='Cancel', fg='gray70', font=('Futura', 20), command= lambda: [msg_return('"Cancel"_button-clicked'), msgbox_window.destroy()])
        msgbox_button1.place(x=438, y=82)
        msgbox_button2 = Button(msgbox_window, text='Okay', fg='gray70', font=('Futura', 20), command= lambda: [msg_return(msgbox_entry1.get()), msgbox_window.destroy()])
        msgbox_button2.place(x=390, y=82)

widget checker whole code:

        
    if msgbox_widgets == 'ok_cancel':
        msgbox_button1 = Button(msgbox_window, text='Cancel', fg='gray70', font=('Futura', 20), command= lambda: [msg_return('"Cancel"_button-clicked'), msgbox_window.destroy()])
        msgbox_button1.place(x=438, y=82)
        msgbox_button2 = Button(msgbox_window, text='Okay', fg='gray70', font=('Futura', 20), command= lambda: [msg_return('"Okay"_button-clicked'), msgbox_window.destroy()])
        msgbox_button2.place(x=390, y=82)
    elif msgbox_widgets == 'input':
        msgbox_entry1 = Entry(msgbox_window, width=32, font=('Futura', 16))
        msgbox_entry1.place(x=145, y=82)
        msgbox_button1 = Button(msgbox_window, text='Cancel', fg='gray70', font=('Futura', 20), command= lambda: [msg_return('"Cancel"_button-clicked'), msgbox_window.destroy()])
        msgbox_button1.place(x=438, y=82)
        msgbox_button2 = Button(msgbox_window, text='Okay', fg='gray70', font=('Futura', 20), command= lambda: [msg_return(msgbox_entry1.get()), msgbox_window.destroy()])
        msgbox_button2.place(x=390, y=82)
    else:
        print('CONSOLE ERROR: No such supported pop-up type: ' + msgbox_type)
    return msg_outputvalue

#Usage: msg_showmsgbox('warning_message', 'title', 'content Hello! Welcome to a brand new oper\nating system corwinus! ', 'ok_cancel')

Basically, I want the user to input something in the entry box and then I want to print it out!
But the output is wrong! It shows the previous value of the entry1.get()!

The first value which was set to the msg_output:

Output:
None

The first output:

Output:
None

but it should be Input No.1
The second output

Output:
Input No.1

but it should be Input No.2
Videos: PLEASE WATCH THE VIDEO CAREFULLY! PAY ATTENTION TO THE IDLE SHELL AND THE TKINTER WINDOWS!

Thanks!

RE: Keeps showing prevuios inputs - Gribouillis - Jan-06-2020

Start by adding print('msg_return({})'.format(repr(returnvalue))) in function msg_return to see if it gets correctly called.

RE: Keeps showing prevuios inputs - Denni - Jan-07-2020

What are you using ? Tkinter, PyQt, PySide2 or something else

RE: Keeps showing prevuios inputs - _ShevaKadu - Jan-08-2020

(Jan-07-2020, 04:01 PM)Denni Wrote: What are you using ? Tkinter, PyQt, PySide2 or something else

I use Tkinter.

RE: Keeps showing prevuios inputs - _ShevaKadu - Feb-15-2020

(Jan-06-2020, 09:34 AM)Gribouillis Wrote: Start by adding print('msg_return({})'.format(repr(returnvalue))) in function msg_return to see if it gets correctly called.

It does @Gribouillis

RE: Keeps showing prevuios inputs - Gribouillis - Feb-17-2020

I'm afraid you'll have to post the whole code. It is difficult to diagnose an error with incomplete information.