Handling a .txt text - Printable Version

Handling a .txt text - Printable Version

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Handling a .txt text - reinalazaro - Jan-09-2020

Hi, Folks! I'm trying to open a .txt file and find a line with a specific expression but the return isn't what I expected:

 f = open("file.txt", "r")

 for line in f: 
   
       if "Net" in line: 
       
           print(line)
       else:
           print("Didn't find")

 f.close()

So, what i get is a lot of "Didn't find" but I know that there's this expression in the file. And, I noticed that if i ask for just one caracter, like "N" instead the "Net", the code returns lines with it.

RE: Handling a .txt text - ichabod801 - Jan-09-2020

What do you get if you take out lines 8 and 9? Are you sure 'Net' is in the line with that capitalization?

RE: Handling a .txt text - Clunk_Head - Jan-09-2020

    if "Net" in line or 'net' in line:

Is it because you need to look for "net" with a lowercase 'n' too?

RE: Handling a .txt text - sandeep_ganga - Jan-09-2020

Try this to see if helps,

f = open("file.txt", "r")

for line in f: 
	#print(line.split(' '))  #splitting the line to list before compare
	for item in line.split(' '): 
		if "NET" in item.upper():
			print(line)
		else:
			pass
 
f.close()

Output:file.txt:

sun moon net
net a b c 
def ghi
n
ij kl
mno pqr
sty ury
mui n pqr
stu net wxy


python 9jan.py

sun moon net
net a b c
stu net wxy

Best Regards,
Sandeep

GANGA SANDEEP KUMAR

RE: Handling a .txt text - perfringo - Jan-09-2020

I suggest to use different style for opening files (using 'with'). In order to verify processing all rows one can use enumerate and printing out:

with open('for_net.txt', 'r') as f:
    for i, row in enumerate(f, start=1):
        if 'net' in row.lower():
            print(f'Row #{i} contains "net": {row.strip()}')
        else:
            print(f'Row #{i} does not contain "net"')

if 'for_net.txt' contains following four rows:

Quote:This is not
but here is net
and not
and net

Code will output:

Output:Row #1 does not contain "net"
Row #2 contains "net": but here is net
Row #3 does not contain "net"
Row #4 contains "net": and net

RE: Handling a .txt text - reinalazaro - Jan-11-2020

Thank you guys for the help!
I'm moving forward with your tips, but it breaks me another issue.

f = open("file.txt", "r")

for line in f:

    for item in line.split(' '):

        if "NET" in item.upper():

            print(line)

        else:
            pass

f.close()

When I open a .txt with more data the return of this code is the error below at PyCharm:

Error:File "C:\Users\Lzr\AppData\Local\Programs\Python\Python37-32\lib\encodings\cp1252.py", line 23, in decode
    return codecs.charmap_decode(input,self.errors,decoding_table)[0]
UnicodeDecodeError: 'charmap' codec can't decode byte 0x81 in position 4748: character maps to <undefined>

I'm wondering there is something wrong in the .txt file but there will be a way to treat this "decode" error.
Thank you again!!

PS.: I liked the way to open the file using 'with'.

RE: Handling a .txt text - Clunk_Head - Jan-11-2020

Try:

f = open("file.txt", encoding='utf-8', errors='ignore')

RE: Handling a .txt text - reinalazaro - Jan-11-2020

It works!!