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+--- Thread: Paramiko SSH "put", destination name (/thread-2524.html)
Paramiko SSH "put", destination name - j.crater - Mar-23-2017
Hello all, I am having difficulties understanding paramiko's behaviour, when it comes to sending files over SSH. I have this function:
def SSH_send_file(file, host, username, password, path): s = paramiko.SSHClient() s.set_missing_host_key_policy(paramiko.AutoAddPolicy()) s.connect(host, 22, username, password) sftp = s.open_sftp() sftp.put(file, path) s.close()For example, you would call it like:
SSH_send_file("file_to_send.txt", "10.20.30.40", "user", "secret", "/tmp")
Until now, it worked fine using it like in the example above. But now (in same program) there was an occassion when this error happened:
Error: File "\lib\site-packages\paramiko\sftp_client.py", line 811, in _convert_status
raise IOError(text)
OSError: FailureSSH_send_file("file_to_send.txt", "10.20.30.40", "user", "secret", "/tmp/file_to_send.txt")
Why did this function "change behaviour", so I had to use it differently in one case, as opposed to previous uses? Can I avoid/predict it in future?
Thank you! JC
RE: Paramiko SSH "put", destination name - buran - Mar-23-2017
well, no experience with paramiko, but only by reading the docs, I would say always include the filename to avoid errors:
Quote:remotepath (str) – the destination path on the SFTP server. Note that the filename should be included. Only specifying a directory may result in an error.
I would say you were just lucky not getting error on previous occasion
RE: Paramiko SSH "put", destination name - j.crater - Mar-23-2017
Alright, behaviour I noticed reflects your quote from the docs. Perhaps I was only lucky so far to not have this error appear. Thank you!