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Taking brackets out of list in print statement - pythonprogrammer - Apr-13-2020 How do I take brackets out of multiple lists in a print statement. Say I have the following lists of numbers: j = [2,5] k = [4,6] e = [7,8] r = [9,1]How would I print "The numbers you have selected are 2,5,4,6,7,8,9,1"? I want to print the numbers from all the lists without the brackets in between. RE: Taking brackets out of list in print statement - deanhystad - Apr-13-2020 An asterisk before a container unpacks the container. *[a, b, c] becomes a, b, c RE: Taking brackets out of list in print statement - bowlofred - Apr-13-2020 Couple of methods: import itertools j = [2,5] k = [4,6] e = [7,8] r = [9,1] #Nested list comprehension items = [str(x) for sublist in [j, k, e, r] for x in sublist] print(f"The numbers you have selected are {','.join(items)}") #chain iterable items2 = ",".join(map(str,itertools.chain(j,k,e,r))) print(f"The numbers you have selected are {items2}")
RE: Taking brackets out of list in print statement - perfringo - Apr-13-2020 Another way without any datatype conversion: j = [2,5] k = [4,6] e = [7,8] r = [9,1] print('The numbers you have selected are', end=' ') print(*j, *k, *e, *r, sep=', ')If one will run this file output will be: If order is not important and you want things more 'human-readable' then you can sort them as well:print('The numbers you have selected are', end=' ') print(*sorted([*j, *k, *e, *r]), sep=', ')This will output:
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