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iPython tab completion of method variable - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: iPython tab completion of method variable (/thread-2653.html) |
iPython tab completion of method variable - sixteenornumber - Mar-31-2017 is there any way to get iPython to recognize the type of "each" in B.printBarList(). for example I want to use tab-complete in iPython so I type "each." but it doesn't know the type. # A.py class A: def __init__(self): self._foo = "FOO" def getFoo(self): return self._foo # B.py from A import A class B: def createBarList(self): '''create 10 instances of A in barList''' barList = [] for i in range(10): barList.append(A()) return barList def printBarList(self, barList): ''' Itter over each A in barList and print each ***MY QUESTION*** the "each" in the loop below ''' for each in barList: print(each.foo) if __name__ == "__main__": b = b() barList = b.createBarList() b.printBarList() Moderator Larz60+: Changed icode tags to Python tags (see help, BBCODE)
RE: iPython tab completion of method variable - sixteenornumber - Apr-04-2017 I found my answer. as of python 3.5 import typing def foo(bar: int) --> int: return bar**2 in ipython when you enter, "foo()" it wll prompt with "bar: int returns int". this also works with class types. class Baz: def __init__(self): pass def foo(bar: Baz) --> None: pass Moderator Larz60+: Added Python tags. Please do this in the future (see help, BBCODE) second notice
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