Python Forum
[Tkinter] Returning always the last image into Label - Printable Version

+- Python Forum (https://python-forum.io)
+-- Forum: Python Coding (https://python-forum.io/Forum-Python-Coding)
+--- Forum: GUI (https://python-forum.io/Forum-GUI)
+--- Thread: [Tkinter] Returning always the last image into Label (/Thread-Tkinter-Returning-always-the-last-image-into-Label)



Returning always the last image into Label - Lucas_Ribeiro - May-08-2020

I'm making a web scrapping on a website for a private game server using Python. In a part of this website prints the result of the last nation war winner and show 2 messages: "Capella Ganhou!!" and "Procyon Ganhou!!" using the BeautfulSoup library. I made a condition for each event for show the winner nation image into the Label by an url. But for some reason it shows always the last image url and I don't know what is happening. Here is the code below:

from tkinter import *
import urllib.request
from bs4 import BeautifulSoup
from IPython.display import Image, display
from PIL import Image, ImageTk
from io import BytesIO

def capella_tg():
    resultado_tg = StringVar()
    try:
        resultado_tg.set(soup.find_all("font")[5].string)
        label_resultado_tg = Label(root, textvariable=resultado_tg, font=("Consolas", 25)).pack()
    except:
        return False

def procyon_tg():
    resultado_tg = StringVar()
    try:
        resultado_tg.set(soup.find_all("font")[4].string[3:])
        label_resultado_tg = Label(root, textvariable=resultado_tg, font=("Consolas", 25)).pack()
    except:
        return False

root = Tk()
root.title("Resultado TG Cabal Ghost")

with urllib.request.urlopen("http://www.cabaleasy.com") as url: page = url.read()
soup = BeautifulSoup(page, "html.parser")

if capella_tg():
    url = "https://i.imgur.com/AHLqtt0.jpg"    
    with urllib.request.urlopen(url) as u: raw_data = u.read()        
    im = Image.open(BytesIO(raw_data))
    image = ImageTk.PhotoImage(im)
    label = Label(image=image).pack()
else:
    procyon_tg()
    url = "https://i.imgur.com/TQyCnfD.jpg"    
    with urllib.request.urlopen(url) as u: raw_data = u.read()        
    im = Image.open(BytesIO(raw_data))
    image = ImageTk.PhotoImage(im)
    label = Label(image=image).pack()


root.mainloop()



RE: Returning always the last image into Label - deanhystad - May-08-2020

The only possible return values for capella_tg() are None or False.