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Format phonenumbers - regular expressions - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: Format phonenumbers - regular expressions (/thread-26727.html) |
Format phonenumbers - regular expressions - Viking - May-11-2020 Hi, I am trying to format a list of phonenumbers. I want to move through the list and do the same operation on each number, I have figured out how to do it one number at a time. Would an option be to add a for loop? import re # List with phonenumbers number = ['072 5674 323', "072 540 6789", "0047735 648975"] # Remove spaces num = re.sub(r'\D', "", number[0]) # Read backwards num_1 = num[-9:] #Print country code + formated number print(F"0047{num_1}") #Output 0047735674323 RE: Format phonenumbers - regular expressions - buran - May-11-2020 (May-11-2020, 06:44 PM)Viking Wrote: Would an option be to add a for loop?yes, or use list comprehension. And no need of regex too numbers = ['072 5674 323', "072 540 6789", "0047735 648975"] formated_numbers = [f"0047{number.replace(' ', '')[-9:]}" for number in numbers] print(formated_numbers
RE: Format phonenumbers - regular expressions - Viking - May-11-2020 Great! Thanks! :) |