UnBoundLocalError - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: UnBoundLocalError (/thread-27230.html) |
UnBoundLocalError - Seaninho - May-30-2020 Hello to everyone! I'm trying to create a code using Python but I have a problem. It gives me this error: I will post here the part of the code where the problem is:def rsf2image(i3): global byte ppm = '%s%d.ppm' % (name,i3) if not os.path.isfile(ppm): command = '< %s %s n3=1 f3=%d | %s %s | %s %s > %s' % \ (byte,sfwindow,i3,sfgrey,args,ppmpen,args,ppm) if os.system(command) or not os.path.isfile(ppm): sys.stderr.write('Failed to execute "%s"\n\n' % command) sys.exit(3) ppms.append(ppm) img = PhotoImage(file=ppm) return img ... image = rsf2image(0)Can someone please help me with this? Thank you very much RE: UnBoundLocalError - menator01 - May-30-2020 The error is suggesting that you are calling img before assigning it on line 67. RE: UnBoundLocalError - pyzyx3qwerty - May-30-2020 (May-30-2020, 09:45 AM)menator01 Wrote: The error is suggesting that you are calling img before assigning it on line 67.He defines img on line 66 (May-30-2020, 08:59 AM)Seaninho Wrote: Hello to everyone!Is this your full code? The problem might be somewhere else too... RE: UnBoundLocalError - azajali43 - May-31-2020 You can solve UnboundLocalError by changing the scope of the variable that complains. You need to explicitly declare the global variable. The scope of the variable x in the printx function is global. You can verify the same by printing the value of x in the terminal and it will be 6. |