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Search in an unsorted list - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: Search in an unsorted list (/thread-27377.html) |
Search in an unsorted list - amir_0402 - Jun-04-2020 Hi guys, I'm trying to create a function that searches a key in an unsorted list with a divide-and-conquer algorithm. Right now it only searches on the right side of the list. How do I manage that it continues searching on the left side of the list? def divcon(List, begin, end, key): if end > len(List) - 1 or begin > len(List) - 1 or end < 0 or begin < 0: return False m = (begin + end) // 2 if (L[m] == key): return True if begin > end: return divcon(List, begin, m – 1, key) else: return divcon(List, m + 1, end, key)I'd be very grateful for any help. RE: Search in an unsorted list - micseydel - Jun-04-2020 If it's unsorted, how do you divide in any reasonable way? Why not just do a linear search? RE: Search in an unsorted list - deanhystad - Jun-04-2020 If elements are not in any order a linear search is most efficient. |