• On the line labeled Input write the following numbers: 4 6 12 9 1 2
  
• Draw a box, label the box S, write the number 0 in box S
  
• Draw a box, label the box C, write the number 0 in box C
  
• Draw a box, label the box X write the number 999 in box X
  
• If there are still numbers on the line labeled Input then do the next instruction, otherwise do instruction 10
  
• Replace the number in box X with the the next number on the line labeled Input, erase from the Input line the number that was copied to box X
  
• Replace the number in box S with the sum of the number that is currently in box S plus the number in box X
  
• Replace the number in box C with the number that is one more than the number currently in box C
  
• If the number in box C is greater than 0 then do the next instruction, otherwise do instruction 14
  
• Draw a box, label the box A, write the value in box S divided by the value in box C in box A
  
• Write the number in box A on the line labeled Output Go to instruction 15 Write the words "No answer" on the Output line
  

list = [4,6,12,9,1,2]
S = 0
C = 0
X = 999
while list[0]:
    S = S + X
    C = C + 1
if C > 0:
    A = S/C
    print(A)
else:
    print("No Answer")

• Put the following numbers in boxes 0 - 5, one number per box: 3, 17, 4, 19, 8, 2
  
• Draw a box, label the box I, write the number 0 in box I
  
• Draw a box, label the box X, write the number 0 in box X
  
• Draw a box, label the box G, copy the number from numbered box 0 to box G
  
• If the number in box I is less than 6 then do the next instruction, otherwise do instruction 10
  
• If the number in the numbered box whose number is the same as the number in box I is greater than the number in box G then do the next instruction, otherwise do instruction 8
  
• Replace the number in box G with the value currently in the numbered box whose number is the same as the number in box I
  
• Replace the number in box X with the number that is in box I
  
• Replace the number in box I with the number that is one more than the number currently in box I
  
• Go back and do instruction 4 again Write the number in box G on the line labeled Output Write the number in box X on the line labeled Output
  

list = [3,17,4,19,8,2]
I = 0
X = 0
G = list()
while I < 6:
    list(I) > G
    G = list(I)
    X = I
    I = I + 1
    print(G)
    print(X)

(Apr-17-2017, 10:42 PM)jhall710 Wrote:

list = [4,6,12,9,1,2]
S = 0
C = 0
X = 999
while list[0]:
    S = S + X
    C = C + 1

(Apr-18-2017, 02:27 AM)jhall710 Wrote: so the program stops once the list is empty

>>> items = [4, 34, 6, 7]
>>> total = 0
>>> while items:
...     total += items.pop()
...
>>> total
51
>>> items
[]

(Apr-18-2017, 02:18 AM)nilamo Wrote: Maybe call it input or items instead?

list_ = [4,6,12,9,1,2]
s = 0
c = 0
x = 999
while len(list_) >0: # here you had list[0] I think you wanted to stop when length reached 0
    for amount in list_: # for loop will go through the list_ of numbers one amount at a time
        x = amount        # the for loop will give individual amounts to x variable.
        s += x                # same as your code S = S + X
        c += 1                # same as your code C = C + 1
        list_.remove(amount) #this is to remove items from your list!

# you don't need to check the counter.  so the if statement could be deleted or reworded so if the program is run and no items are on the list it says NO ITEMS! else it prints A

(Apr-24-2017, 03:43 AM)nilamo Wrote: Modifying a list while you're in the middle of iterating over that same list is very dangerous.