How to add date and years(integer) to get a date - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: How to add date and years(integer) to get a date (/thread-29448.html) |
How to add date and years(integer) to get a date - NG0824 - Sep-02-2020 I am trying to add years in integer form in date to get final output as date. Could anyone help with syntax. RE: How to add date and years(integer) to get a date - buran - Sep-02-2020 show us what have you tried, sample input and expected output probably https://docs.python.org/3/library/datetime.html#datetime.date.replace or https://docs.python.org/3/library/datetime.html#datetime.datetime.replace RE: How to add date and years(integer) to get a date - jefsummers - Sep-02-2020 What have you tried? Show us your code and where you are stuck. Have you tried timedelta(days=years*365) but got stuck on leap years? RE: How to add date and years(integer) to get a date - DeaD_EyE - Sep-03-2020 (Sep-02-2020, 07:22 PM)NG0824 Wrote: I am trying to add years in integer form in date to get final output as date. Could anyone help with syntax. In [1]: import datetime In [2]: now = datetime.datetime.now() In [3]: print(now) 2020-09-03 10:01:22.062401 In [4]: # set a year ...: past = now.replace(year=1900) In [5]: print(past) 1900-09-03 10:01:22.062401 In [6]: # adding years to current year ...: future = now.replace(now.year + 10) # 10 years in future In [7]: leap_year = datetime.datetime(2020, 2, 29) # impossible date for non-leap years In [8]: print(leap_year) 2020-02-29 00:00:00 In [9]: leap_year.replace(year=2019) # booom --------------------------------------------------------------------------- ValueError Traceback (most recent call last) <ipython-input-9-164fec2883be> in <module> ----> 1 leap_year.replace(year=2019) # booom ValueError: day is out of range for monthIf you wonder, this comes from IPython. A better REPL for Python. Working with dates is not always straightforward. Sometimes it ends into impossible dates. To catch this leap_error: import datetime one_day = datetime.timedelta(days=1) leap_year = datetime.datetime(2020, 2, 29) new_year = 2019 try: new_dt = leap_year.replace(year=new_year) except ValueError: new_dt = (leap_year + one_day).replace(year=new_year)Important stuff to read:
I hope this pushes you in the right direction. Just keep in mind, that the replace method does not change the object itself, it returns a new modified datetime object. RE: How to add date and years(integer) to get a date - NG0824 - Sep-03-2020 Thanks everyone, I was able to solve this error by firt installing datedelta and then used datedelat.datedelta(years=fieldname()) |