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+--- Thread: Skipping a line on output (/thread-3057.html)
Skipping a line on output - lucas0150 - Apr-27-2017
Hi.
Sorry for the poor English, I'm not a native speaker.
The boring code I'm writing works as follows. The user inputs a number T. The user is then prompted, T times, to provide a couple of values A and N, such that the N integers that come after A and their sum will be printed as the output. I've worked everything out just fine, but I'm supposed to get the sequence of integers in a line and their sum on another line, otherwise the automatic corrector my retarded professor uses won't accept it. To print the sequence in the same line, I used the argument end = ' '. However, this argument makes everything that comes after it appear on a single line, and the sum is supposed to appear in a new line. What I mean is, if you type 1 3, you're supposed to get
1 2 3
6
But my program gives
1 2 3 6
So, how do I make the sum of the numbers appear on a new line? Here's my code. The three final lines are what's really important.
T = int(input('Number of pairs: '))
lizt = []
for i1 in range(1, T):
A, N = input('Insert a couple of numbers').split()
A, N = int(A),int(N)
for i2 in range(A, A+N):
lizt.append(i2)
print(i2, end =' ')
sm = sum(lizt)
print(sm)
RE: Skipping a line on output - Larz60+ - Apr-27-2017
The end = ' ' causes no line feed to be issed
use a formatting statement as follows:
print('\nSum of numbers: {}'.format(sm))
RE: Skipping a line on output - lucas0150 - Apr-27-2017
(Apr-27-2017, 01:56 AM)Larz60+ Wrote: The end = ' ' causes no line feed to be issed
use a formatting statement as follows:
print('\nSum of numbers: {}'.format(sm))
Oh, that works. Thanks a lot man
RE: Skipping a line on output - Ofnuts - Apr-27-2017
Using
\n at the beginning of print() statements can create problems because console output actually produces an output when it sees the \n (line buffering). Using a print() without arguments will add a linefeed in the output.IMHO the OP would have better used a
join() instead of multiple print(...) anyway.