How to get index of minimum element between 3 & 8 in list - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: How to get index of minimum element between 3 & 8 in list (/thread-30856.html) How to get index of minimum element between 3 & 8 in list - Mekala - Nov-10-2020 Hi, I have the below list, and I want to get the index of minimum element which is >3 & <=8. ```my_list = [-1,4,-5,0,2,11,9,8,6] #below only grep minimum whose value >0 m = min(i for i in my_list if i > 0) but I want a minimum element between 3 & 8 I use the below code, but it does not work. It still gives me an answer is 2. m2 = min(i for i in my_list if i > 0 & i<=8)```Someone help, how to achieve this. RE: How to get index of minimum element between 3 & 8 in list - perfringo - Nov-10-2020 If your condition is `i > 0` then 2 is the correct answer. In order to avoid such typos it is more readable to write: ```>>> my_list = [-1,4,-5,0,2,11,9,8,6] >>> min(item for item in my_list if 3 < item <= 8) 4``` RE: How to get index of minimum element between 3 & 8 in list - DeaD_EyE - Nov-10-2020 A different form: ```def condition(x): return 3 < x <= 8 my_list = [-1,4,-5,0,2,11,9,8,6] minimum = min(filter(condition, my_list)) print("Minimum is", minimum)```I use it very rare. There are so many possibilities to solve this.