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Counting Element in Multidimensional List - quest_ - Nov-25-2020 Hello, I have list like that: Now I want to countFirst how many [000], [001] ,[010],[011]…(all triplet combinations of 0 and 1) according to last element of the array (last element are (1.57, 0, 1.57),(0, 1.57, 0),(1.57, 0, 0)…) For instance in the first sublist I have 3 times [0, 1, 1] 1 times [111], 1 times [000] and 1 times [101] and for the forst sublist I have 7 elements except (0, 1.57, 0) Second, I want to count how many element there are of each subarray except last element (last elements means that element is inside ()) For instance in the first sublist I have 7 element except (0, 1.57, 0) I can count somethong woth the following line but it counts total [000], [001] ,[010],[011]… I want to count sublist by sublist triplets = tuple(itertools.product((0, 1), repeat = 3)) for triple in triplets: sums[triple] = sum(np.all((newlist22-np.array(triple))==0, axis=1))How can I solve this problem Thanks for helps... RE: Counting Element in Multidimensional List - quest_ - Nov-25-2020 Ok I found :) triplets = tuple(itertools.product((0, 1), repeat = 3)) sums = {} for row in newlist2: for triple in triplets: sums[triple] = sum(np.all((row-np.array(triple))==0, axis=1)) print(sums) |