+- Python Forum (https://python-forum.io)
+-- Forum: Python Coding (https://python-forum.io/forum-7.html)
+--- Forum: Homework (https://python-forum.io/forum-9.html)
+--- Thread: If / loops help (/thread-31233.html)
If / loops help - kam_uk - Nov-29-2020
Hi
I am going through the Python Crash Course book, and answering the questions in each chapter.
I'm stuck at one.
The question is:
1. Create a list of numbers from 1 - 9
2. Loop through the list and using if-elif-else the output should read "1st 2nd 3rd" etc with each result on the new line.
So I did this:
numbers_list = list(range(1,10))
print(numbers_list)
for number in numbers_list:
if number == '1':
print(f"{number}st")I printed the list as soon as I created it to make sure that was ok, which it was.I then created a for loop to go through each number. I tested '1' but that doesn't seem to work.
Any ideas?
RE: If / loops help - deanhystad - Nov-29-2020
1, not '1'. '1' is a string, not a number. list(range(1,10)) makes a list of numbers.
RE: If / loops help - jefsummers - Nov-29-2020
Also, you haven't handled 2nd, 3rd, and 4th-9th
RE: If / loops help - GirishaSJ - Dec-03-2020
As you are trying to read the integer values stored on your "numbers_list" by a string value of "1" , so the if loop will fail always.
You can try , with 2 ways :
#One way
numbers = list(range(1,11))
#range(1,10) or range(1,11) based on your requirement
print(numbers)
for num in numbers:
if(num==1):
print(num)
elif(num==2):
print(num)
else:
if(num==3):
print(num)
else:
continue
#Second way
for num in numbers:
if(num<=3):
print(num)
else:
continue
RE: If / loops help - buran - Dec-03-2020
Just to mention that there is no need to add brackets around the condition (unless it's really necessary for precedence).
if num <= 3: is just fine. Also no need to add redundant else: continue