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+--- Thread: index error (/thread-31342.html)
index error - surim - Dec-05-2020
I don't know why these codes makes error message.
Please help me
def dynamic_sort(C):
C.sort(key = lambda x: x[1])
n = len(C)
cache = []
for y in range(0, n):
cache.append(C[y][2])
return cache
def dynamic_job(C):
cache = dynamic_sort(C)
n = len(C)
for i in range(1, n+1):
for k in range(0, i):
if C[k][1] <= C[i][0]: #this line makes the error message(IndexError: list index out of range)
if cache[k] + C[i][2] > cache[i]:
cache[i] = cache[k] + C[i][2]
max = 0
for i in range (0, n+1):
if max < cache[i]:
max = cache[i]
return max
C = [[2,5,6], [4,6,5], [6,7,4], [1,3,5], [5,8,11], [7,9,2]]
print(dynamic_job(C))
RE: index error - buran - Dec-05-2020
Please, post the entire traceback that you get. We need to see the whole thing.
Take a time to read What to include in a post
RE: index error - surim - Dec-05-2020
(Dec-05-2020, 09:51 AM)surim Wrote: I don't know why these codes makes error message.
Please help me
def dynamic_sort(C): C.sort(key = lambda x: x[1]) n = len(C) cache = [] for y in range(0, n): cache.append(C[y][2]) return cache def dynamic_job(C): cache = dynamic_sort(C) n = len(C) for i in range(1, n+1): for k in range(0, i): if C[k][1] <= C[i][0]: #this line makes the error message(IndexError: list index out of range) if cache[k] + C[i][2] > cache[i]: cache[i] = cache[k] + C[i][2] max = 0 for i in range (0, n+1): if max < cache[i]: max = cache[i] return max C = [[2,5,6], [4,6,5], [6,7,4], [1,3,5], [5,8,11], [7,9,2]] print(dynamic_job(C))
Error:Traceback (most recent call last):
File "F:/알개/dynamin_jobschedule.py", line 32, in <module>
print(dynamic_job(C))
File "F:/알개/dynamin_jobschedule.py", line 16, in dynamic_job
if C[k][1] <= C[i][0]:
IndexError: list index out of rangeRE: index error - surim - Dec-05-2020
thank you for your reply and I added whole the error messages.
RE: index error - deanhystad - Dec-05-2020
n = len(C)
for i in range(1, n+1):
for k in range(0, i):
if C[k][1] <= C[i][0]: n is the number of things in C. In Python the first index is 0 and the last index is len-1. If n is 3 there is a C[0], C[1] and C[2]. If you tried to get C[3] you will get a "list index out of range" error because there is no C[3].When you do the loop "for i in range(1, n+1)" you try to look at C[n]. Remember that the possible index numbers range from 0 to len-1, so
C[len(C)] is out of range.