concatenat - shutil - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: concatenat - shutil (/thread-32461.html) |
concatenat - shutil - jmabrito - Feb-10-2021 import shutil t1 = 'bjjj' t2 = 4455 t3 = '.txt' t6 = print(t1+str(t2)+t3) shutil.copy('bjjj.txt', 't6') shutil.copy('bjjj.txt', 'bjjj4455.txt') NOTE NOTE I have a job file called bjjj.txt. When the program ended, I wanted it to be copied to the same name concatenated with a variable. I made immense attempts to no avail. If you put fixed bjjj4455.txt it works perfectly. But I want to increase the number 4455 +1 ... Thank you RE: concatenat - shutil - BashBedlam - Feb-10-2021 Is this what your are looking for? prefix = 'bjjj' version_number = 4455 version_number += 1 sufix = '.txt' new_file_name = f'{prefix}{version_number}{sufix}' shutil.copy('bjjj.txt', new_file_name)or condensed: new_file_name = f'bjjj{version_number}.txt' RE: concatenat - shutil - jmabrito - Feb-11-2021 thank you. what should I do to complete this request of mine. Worked perfectly. thanks again RE: concatenat - shutil - jmabrito - Feb-11-2021 (Feb-10-2021, 11:21 PM)BashBedlam Wrote: Is this what your are looking for?100% sorted out I have a problem to finalize the program for the post subject "goto". there is a line in the "for _ in range (1)" cycle that says "print (f '{k} EXISTS')" must go back to for _, as this number that exists should not be announced. please, can you help me?! In the hands of a good programmer, it should be easy. Do you have access to my GOTO order? |