Send UDP packet after bind - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: Networking (https://python-forum.io/forum-12.html) +--- Thread: Send UDP packet after bind (/thread-32868.html) |
Send UDP packet after bind - pacmyc - Mar-11-2021 I want to send a UDP packet to 192.168.0.155 and then listen for replies on the same port as I sent the packet from. The below code doesn't work. I can't invoke s.sendto after I have binded the socket. Any suggestions? import socket import sys ip = "127.0.0.1" port = 42134 # Create a UDP socket s = socket.socket(socket.AF_INET, socket.SOCK_DGRAM) # Bind the socket to the port server_address = (ip, port) s.bind(server_address) print("Do Ctrl+c to exit the program !!") send_data = 'B:reglistener' s.sendto(send_data.encode('utf-8'), ("192.168.0.155", 42314)) while True: print("####### Server is listening #######") data, address = s.recvfrom(4096) print("\n\n 2. Server received: ", data.decode('utf-8'), "\n\n") send_data = input("Type some text to send => ") s.sendto(send_data.encode('utf-8'), address) print("\n\n 1. Server sent : ", send_data,"\n\n") |