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+--- Thread: If match not found print last line (/thread-33431.html)
If match not found print last line - tester_V - Apr-25-2021
Greetings!
I need to print the last line of a file if a match (second match) not found.
I'm printing all the lines with "match-2" for each "match-1" line.
line-1 match-1
line something else
line something else
line-4 match-2
line-5 match-2
line-6 match-2
line something else
line something else
line something else
line something else
line-11 match-1
line something else
line something else
line-14 match-2
line something else
line something else
line-17 last match-1
line-18 last need to print
Here is the code I got so far:
with open('C:/02/file2.txt','r') as mf :
for el in mf :
el=el.strip()
if 'match-1' in el :
one=el.strip()
#print ("one "+one)
elif 'match-2' in el :
tr = el
print(one+" , "+tr) Code prints :line-1 match-1 , line-4 match-2
line-1 match-1 , line-5 match-2
line-1 match-1 , line-6 match-2
line-11 match-1 , line-14 match-2
Need also to print :
line-17 last match-1 , line-18 last need to print
Thank you!
RE: If match not found print last line - menator01 - Apr-25-2021
Maybe not the best way but might help
#! /usr/bin/env python3
matches = []
with open('file.txt') as file:
lines = file.readlines()
for line in lines:
if 'match-1' in line or 'match-2' in line:
matches.append(line)
print(line.strip())
if len(matches) % 2 != 0:
print(lines[-1])Output:line-1 match-1
line-4 match-2
line-5 match-2
line-6 match-2
line-11 match-1
line-14 match-2
line-17 last match-1
line-18 last need to printRE: If match not found print last line - tester_V - Apr-26-2021
I like your thought!
It is great but I need to go with a line-by-line checking the file, it is not a small file and no tone file.
Thank you!