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+--- Thread: Could Someone help me with List problem (/thread-34137.html)
Could Someone help me with List problem - alexsendlegames100 - Jun-30-2021
import math
A = list(map(int, input()))
B = list(map(int, input()))
#C = list(map(int, input()))
if A,B < len(3):
print(D_1)
else:
print(D_2)
D_1 = math.sqrt( (B[0]-A[0])**2 + (B[1]-A[1])**2 + (B[2]-A[2])**2 )
D_2 = math.sqrt( (B[0]-A[0])**2 + (B[1]-A[1])**2 )i tried to create a code that will calculate the distance between two points and it succeed but when i try to do the conditional part to make two option if the vector has two values x and y it will print D_2 and if it has x y z it will print D_1 but it shows a lot of mistakes i dont know how to state the a condition which will check the amount of values in the lists and print one of two solution according the amount of values there 3 or less???
RE: Could Someone help me with List problem - menator01 - Jun-30-2021
One way to check the length of a list
#! /usr/bin/env python3
print('Enter two or three numbers seperated by a space')
while True:
A = input('>> ').split()
if len(A) == 3:
print(f'A has {len(A)} elements')
print(A)
break;
elif len(A) == 2:
print(f'A has {len(A)} elements')
print(A)
break
else:
print('Please enter either 2 or three numbers seperated by a space')
continueOutput:Enter two or three numbers seperated by a space
>> 5
Please enter either two or three numbers seperated by a space
>> 6 2
A has 2 elements
['6', '2']