Put zero for x axis values - Printable Version

Put zero for x axis values - Printable Version

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Put zero for x axis values - quest - Jul-28-2021

Hello,
I have this dict:

od = OrderedDict([(0, 1), (1, 1), (3, 1), (7, 1), (36, 1)])

And I am plotting this array with the following line:

plt.bar(range(len(od)), list(od.values()), align='center')
plt.xticks(range(len(od)), list(od.keys()),rotation='vertical')

IN this example for x axis, I have 0,1,3,7,36. However I don't have 2 between 1 and 3 and I don't have any other numbers between 7 and 36. So I want to update my dict like that:

od=([(0, 1), (1, 1),(2,0), (3, 1), (7, 1), (8,0),(9,0),(10,0),(11,0),...(36, 1)])

How can I do that?

I tried this way:

finalarray=np.zeros(60) # or sth larger than max (input dict keys)
for k,v in  od: 
    print(k,v)
    finalarray[k]=v

And I got this error:

Error:
TypeError: cannot unpack non-iterable int object

RE: Put zero for x axis values - Larz60+ - Jul-29-2021

I think what you wanted was (line 1):

od = OrderedDict([(0, 1), (1, 1), (3, 1), (7, 1), (36, 1)])

and assuming this code is in same script:

finalarray=np.zeros(60) # or sth larger than max (input dict keys)
for k,v in  od: 
    print(k,v)
    finalarray[k]=v

RE: Put zero for x axis values - quest - Jul-29-2021

(Jul-29-2021, 01:59 AM)Larz60+ Wrote: I think what you wanted was (line 1):
od = OrderedDict([(0, 1), (1, 1), (3, 1), (7, 1), (36, 1)])
and assuming this code is in same script:
finalarray=np.zeros(60) # or sth larger than max (input dict keys)
for k,v in  od: 
    print(k,v)
    finalarray[k]=v

Thanks for corrections but I still could not solve my problem

RE: Put zero for x axis values - quest - Jul-29-2021

okay, problem has been solved:

for k,v in  list(od.items()): 
      print(k,v)
      finalarray[k]=v

RE: Put zero for x axis values - DeaD_EyE - Jul-29-2021

I guess there is a better solution for matplotlib to fill the gaps.

A function which looks for the gaps and fill them:

def continious_keys(mapping, fillvalue=0):
    last = None
    
    for key, value in mapping.items():
        
        if last is None:
            yield key, value
            last = key
        else:
            while last + 1 < key:
                last += 1
                yield last, fillvalue
                
            yield key, value
            last = key

It's a generator, so you have to consume it. For example you can use a OrderedDict again.

from collections import OrderedDict


od = OrderedDict([(0, 1), (1, 1), (3, 1), (7, 1), (36, 1)])
generator = continious_keys(od)
new_od = OrderedDict(generator) # <- consumes the generator, creates a new OrderedDict

To make it better visible, I used as fillvalue=math.nan, which is not a number.
Example output from repl:

Output:OrderedDict([(0, 1),
             (1, 1),
             (2, nan),
             (3, 1),
             (4, nan),
             (5, nan),
             (6, nan),
             (7, 1),
             (8, nan),
             (9, nan),
             (10, nan),
             (11, nan),
             (12, nan),
             (13, nan),
             (14, nan),
             (15, nan),
             (16, nan),
             (17, nan),
             (18, nan),
             (19, nan),
             (20, nan),
             (21, nan),
             (22, nan),
             (23, nan),
             (24, nan),
             (25, nan),
             (26, nan),
             (27, nan),
             (28, nan),
             (29, nan),
             (30, nan),
             (31, nan),
             (32, nan),
             (33, nan),
             (34, nan),
             (35, nan),
             (36, 1)])