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+--- Forum: Homework (https://python-forum.io/forum-9.html)
+--- Thread: Homework( Solution found) (/thread-35223.html)
Homework( Solution found) - Zaochen - Oct-10-2021
hello just starded to following studies in python but there are short(4h once in 2 weeks) and dont explain everything what we get in in our homework
so i have a question on how to find a specific number in a loop and print it how many time it was in that loop i did tried with .count() but i do get an error that its not possible with int AttributeError: 'int' object has no attribute 'count'
i did try and other options but really cant find this one
and im already sitting for few hours on this one
for x in range(1,5):
num=int(input('number: '))
print(num.count(0))my home work is to find 0 where user put in numbers Each of the following n lines contains one integer.
Count and print the number of 0
like
Output:#input
10
0
30
20
0
30
50
#output
'number of 0's is 2'RE: Homework( Solution found) - Daring_T - Dec-23-2021
I am not exactly sure on the matter of input? Is it only 7 numbers? Here are two different versions of what I think they're asking for.
# This version finds how many 0's out each iteration of the loop
zeros = 0
for x in range(1, 7):
if int(input('number: ')) == 0:
zeros = zeros + 1
print(f"number of 0's is {zeros}")# This version asks for the 7 numbers first then counts the amount 0's after
nums = []
for x in range(1, 7):
num = int(input('number: '))
print(num)
nums.append(num)
# nums = [10, 0, 30, 20, 0, 30, 50]
zeros = nums.count(0)
print(f"number of 0's is {zeros}")
RE: Homework( Solution found) - BashBedlam - Dec-23-2021
It would me much easier if you left the input numbers as strings instead of changing them to intergers.
# This version asks for the 7 numbers first then counts the amount 0's after
nums = ''
for x in range(7):
num = input('number: ')
nums = nums + num
zeros = nums.count('0')
print(f"number of 0's is {zeros}")