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+--- Thread: [Tkinter] filedialog, open a file error (/thread-38897.html)
filedialog, open a file error - liketocode - Dec-07-2022
Hello
I would like to know how to avoid an error when i close the window instead of choosing a file to open.
Window that show after clicking on "open" button.
from tkinter import *
from tkinter import filedialog
def openFile():
filepath = filedialog.askopenfilename(initialdir="C:\\Test",
title="Open file okay?",
filetypes=(("text files", "*.txt"),
("all files", "*.*")))
file = open(filepath, 'r')
print(file.read())
file.close()
window = Tk()
button = Button(text="Open",command=openFile)
button.pack()
window.mainloop()Error:Exception in Tkinter callback
Traceback (most recent call last):
File "C:\Users\Papa Smurf\AppData\Local\Programs\Python\Python37\lib\tkinter\__init__.py", line 1705, in __call__
return self.func(*args)
File "C:/Users/Papa Smurf/PycharmProjects/Pythonbasics/test/open1.py", line 9, in openFile
file = open(filepath, 'r')
FileNotFoundError: [Errno 2] No such file or directory: ''RE: filedialog, open a file error - deanhystad - Dec-07-2022
Check the filepath. It will be an empty str if no file is selected.
You should answer these kinds of questions yourself. All you needed to do is set a breakpoint on line 9 and display what is returned when you cancel the file dialog. Or you could use a print statement, or you could read the documentation for the tkinter file dialog. Any of these would show you that the len(filepath)==0 when the selection is canceled.
def openFile():
filepath = filedialog.askopenfilename(title="Open file okay?")
print(len(filepath))
window = Tk()
button = Button(text="Open",command=openFile)
button.pack()
window.mainloop()Output:0
63RE: filedialog, open a file error - liketocode - Dec-07-2022
Gee...Thx ! I'm still begginer so i miss things that are so obvious
def openFile():
filepath = filedialog.askopenfilename(initialdir="C:\\Test",
title="Open file okay?",
filetypes=(("text files", "*.txt"),
("all files", "*.*")))
if len(filepath) == 0:
return
file = open(filepath, 'r')
print(file.read())
file.close()
RE: filedialog, open a file error - deanhystad - Dec-07-2022
It is exactly because you are a beginner that doing little experiments to try to understand what is happening is so important. If you dive in and figure things out for yourself your learning will progress at a much faster pace.
RE: filedialog, open a file error - liketocode - Dec-07-2022
Agree
