passing dictionary to the function

passing dictionary to the function - Printable Version

+- Python Forum (https://python-forum.io)
+-- Forum: Python Coding (https://python-forum.io/forum-7.html)
+--- Forum: General Coding Help (https://python-forum.io/forum-8.html)
+--- Thread: passing dictionary to the function (/thread-39008.html)

passing dictionary to the function - mark588 - Dec-19-2022

I have got a dictionary of multiple npy files together and I want pass this dictionary as a parameter to get a comparison score.
I am not sure how to pass them to the function as 2 different subjs.
as function needs 2 paramters to compare and to print the comparsion score.
Thanks for help

RE: passing dictionary to the function - menator01 - Dec-19-2022

One way

dict1 = {
    'key1': 1,
    'key2': 2
}

dict2 = {
    'key': 1,
    'key4': 4
}

def myfunction (arg1, arg2):
    if arg1 == arg2:
        return 'Dicts are equal'
    return 'Dicts do not match'

print(myfunction(dict1, dict2))

You may also want to look at deepdiff from pypi

RE: passing dictionary to the function - deanhystad - Dec-19-2022

I think the OP is asking about something more like this:

stuff = [{'key1': 1, 'key2': 2}, {'key': 1, 'key2: 4}]

or maybe

stuff = {"dict1": {'key1': 1, 'key2': 2}, "dict2": {'key': 1, 'key2: 4}}

Either way you use indexing to get the dictionaries you want to compare.

compare(stuff[0], stuff[1])
compare(stuff["dict1"], stuff["dict2"])