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+--- Thread: [PyQt] choose checkbox (/thread-39434.html)
choose checkbox - devilonline - Feb-16-2023
Hi, I have this code with pyqt5:
elif (content1 == "next"):
todos = ["one" , "two" , "three" , "four", "five"]
self.todo_listWidget.show()
for todo in todos:
item = QListWidgetItem(todo)
item.setFlags(item.flags() | QtCore.Qt.ItemIsUserCheckable)
item.setCheckState(QtCore.Qt.Unchecked)
self.todo_listWidget.addItem(item)And I want if i chose one item make somethinglike if item (x) is checked then do something
how can i do this?
RE: choose checkbox - Axel_Erfurt - Feb-17-2023
Getting signals from QListWidgetItem is difficult, QCheckbox is easier
from PyQt5.QtWidgets import (QMainWindow, QApplication, QVBoxLayout,
QWidget, QCheckBox)
from PyQt5.QtCore import Qt
class mainWin(QMainWindow):
def __init__(self, parent = None):
super(mainWin, self).__init__(parent)
self.setupUI()
def setupUI(self):
self.setGeometry(0, 0, 800, 600)
central_widget = QWidget()
vbox = QVBoxLayout()
todos = ["one" , "two" , "three" , "four", "five"]
self.todo_listWidget = QVBoxLayout()
for todo in todos:
item = QCheckBox(text = todo)
item.setCheckState(Qt.Unchecked)
item.stateChanged.connect(self.test)
self.todo_listWidget.addWidget(item)
vbox.addLayout(self.todo_listWidget)
vbox.addWidget(QWidget())
central_widget.setLayout(vbox)
self.setCentralWidget(central_widget)
def test(self):
action = self.sender()
if action:
state = action.checkState()
name = action.text()
print(f"{name} state: {state}")
if __name__ == '__main__':
import sys
app = QApplication(sys.argv)
win = mainWin()
win.setWindowTitle("Main Window")
win.show()
sys.exit(app.exec_())