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+--- Thread: print within function (/thread-4375.html)
print within function - zpetsch - Aug-11-2017
I am writing a simple converter to change a bearing to a polar coordinate. I'm not quite sure what I'm doing wrong, but the code below won't print the value of the conversion before moving to anotherPolar():
def polar():
direction = input("North or South?")
angle = input("Angle from N Or S:")
secondary = input("East or West?")
polarangle = 0
if direction == 'N' or direction == 'North':
if secondary == 'E' or secondary == 'East':
polarangle = round(90 - float(angle),4)
return polarangle
elif secondary == 'W' or secondary == 'West':
polarangle = round(90 + float(angle),4)
return polarangle
elif direction == 'S'or direction == 'South':
if secondary == 'E' or secondary == 'East':
polarangle = round(270 + float(angle),4)
return polarangle
elif secondary == 'W' or secondary == 'West':
polarangle = round(270 - float(angle),4)
return polarangle
print(polarangle)
polar()
def anotherPolar():
again = input("Another?:")
if again.lower() == "y" or again.lower() == "yes":
polar()
anotherPolar()
elif again.lower() == "n" or again.lower() == "no":
print("Goodbye")
else:
print("Invalid Entry")
anotherPolar()
anotherPolar()
RE: print within function - wavic - Aug-11-2017
Hello! In polar() definition if the first if is passed the nested if statements have return statement. So if return is executed the function is not working enymore and the last line with the print(powarangle) doesn't execute.
RE: print within function - zpetsch - Aug-11-2017
Awesome, thank you so much!