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+--- Thread: python append (/thread-4616.html)
python append - dwiga - Aug-30-2017
I am stuck on my code,
that's why I coming here because a lot of python master that solve my question...
a = "1,2,3"
ax = a.split(",")
jo = []
for b in ax:
if b == "1":
c = "a"
elif b == "2":
c = "b"
elif b == "3":
c = "c"
jo.append(c)
print(jo)and what i get is,Output:['a']
['a', 'b']
['a', 'b', 'c']Output:['a', 'b', 'c']thank you in advance
RE: python append - j.crater - Aug-30-2017
Hi, your print statement on line #14 is inside the for loop. That means the line gets executed on each loop run, with intermediate values of "jo". If you only want it to print the final result, place the print statement outside the loop, which will execute it only once - when the loop has finished.
RE: python append - ichabod801 - Aug-30-2017
Note that to place it outside the loop, you un-indent it so it has the same indentation as the for statement.
RE: python append - dwiga - Aug-31-2017
I did this before
a = "1,2,3"
ax = a.split(",")
jo = []
for b in ax:
if b == "1":
c = "a"
elif b == "2":
c = "b"
elif b == "3":
c = "c"
jo.append(c)
print(jo)and it return isOutput:['c']thanks all, I get what i want now...
a = "1,2,3"
ax = a.split(",")
jo = []
for b in ax:
if b == "1":
c = "a"
elif b == "2":
c = "b"
elif b == "3":
c = "c"
jo.append(c)
print(jo)Output:['a', 'b', 'c']RE: python append - Sagar - Aug-31-2017
Your print was inside the for loop.
RE: python append - dwiga - Sep-04-2017
(Aug-31-2017, 07:50 AM)Sagar Wrote: Your print was inside the for loop.
OK, thanks