Vowels and Consonants detector

Vowels and Consonants detector - Printable Version

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Vowels and Consonants detector - OmarSinno - Sep-21-2017

Objective is: to print True when it's a vowel, and False when it's a consonant, WITHOUT using if conditions.

vowels = ['o', 'i', 'y', 'e', 'a','u']
consonants =['b, c, d, f, g, h, j, k, l, m ,n ,p, q, r, s, t, v, w, x, z']

def is_vowel(c):
    for character in vowels:
        print(True)
    for character in consonants:
        print(False)

is_vowel('banana')

Here's what I got when I executed the program:

True
True
True
True
True
True
False

This is obviously false because I should get False True False True False True.
Any help?

RE: Vowels and Consonants detector - buran - Sep-21-2017

execute

vowels = ['o', 'i', 'y', 'e', 'a','u']
consonants =['b, c, d, f, g, h, j, k, l, m ,n ,p, q, r, s, t, v, w, x, z']
 
def is_vowel(c):
    for character in vowels:
        print(character, True)
    for character in consonants:
        print(character, False)
 
is_vowel('banana')

this will help to see what your script ACTUALLY does

(Sep-21-2017, 09:57 AM)OmarSinno Wrote: Objective is: to print True when it's a vowel, and False when it's a consonant, WITHOUT using if conditions.
vowels = ['o', 'i', 'y', 'e', 'a','u']
consonants =['b, c, d, f, g, h, j, k, l, m ,n ,p, q, r, s, t, v, w, x, z']

def is_vowel(c):
for character in vowels:
print(True)
for character in consonants:
print(False)

is_vowel('banana')
Here's what I got when I executed the program:
True
True
True
True
True
True
False
This is obviously false because I should get False True False True False True.
Any help?

RE: Vowels and Consonants detector - Sagar - Sep-21-2017

You are not using "c" which is passed into the function is_vowel()

RE: Vowels and Consonants detector - j.crater - Sep-21-2017

You have an argument "c" that you pass to the function is_vowel, but where/how do you use it?
Also, compare how you have defined vowels and consonants lists (or what they contain rather).

RE: Vowels and Consonants detector - OmarSinno - Sep-21-2017

Isn't c the string that is supposed to be called later on in the code?

def is_vowel(c):
    for character in c:
        print(character, True)
    for character in c:
        print(character, False)

I adjusted it to this code, still giving me the same results.

I have realized that when it's finding a vowel, it is printing True 6 times, which is the length of the string 'banana'. Same thing goes for when it finds a consonant.
Unlike this code:

def is_vowel2(c):
    for character in c: #The Character in the word defined by the letter "c"
        if character in vowels: #If this character is in the list "vowels"
            print(True) #The statement is then a vowel, which is true!
        else: #If not, or if else
            print(False) #The statement is false, then it is a consonant!

Fortunately, I have to do it both ways (using if conditionals and without using them) so I can actually study both. Help?

RE: Vowels and Consonants detector - buran - Sep-21-2017

vowels = ['o', 'i', 'y', 'e', 'a','u']
def is_vowel2(my_word):
    for character in my_word: #The Character in the word defined by the letter "c"
        print (character in vowels) #If this character is in the list "vowels" print True, else will print False
is_vowel('banana')

vowels = ['o', 'i', 'y', 'e', 'a','u']
def is_vowel(c):
    return c in vowels #If this character is in the list "vowels" print True, else will print False
for character in 'banana':
    print(is_vowel2(character))