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+--- Thread: Error in a "for" loop (/thread-5979.html)
Error in a "for" loop - sylas - Oct-31-2017
Hi all! It seems easy but it is not. Thanks for your help.
print("quick_average.py")
text = "13 16 19 23"
x = text.split()
print(x) # x is a list of sytrigs
print(x[0]) # print first item
print(float(x[0])) # convert string to number
print("convert the whole list" =
for i in range(4): # syntax error
# for i in text.split(): #syntax error
print(x[i])
print(float(x[i]))Error:/usr/bin/python3.5 /home/sylvain/PycharmProjects/Py2/quick_average.py
File "/home/sylvain/PycharmProjects/Py2/quick_average.py", line 8
for i in range(4):
^
SyntaxError: invalid syntax
Process finished with exit code 1tagged code:
print("quick_average.py")
text = "13 16 19 23"
x = text.split()
print(x) # x is a list of sytrigs
print(x[0]) # print first item
print(float(x[0])) # convert string to number
print("convert the whole list" =
for i in range(4): # syntax error
# for i in text.split(): #syntax error
print(x[i])
print(float(x[i]))
RE: Error in a "for" loop - buran - Oct-31-2017
check your line 7
RE: Error in a "for" loop - sylas - Oct-31-2017
Thank you Buran. You have good eyes, but not me.
RE: Error in a "for" loop - nilamo - Oct-31-2017
Sometimes, with Syntax errors, you need to check the line before where it says the error is. And that's because of things like this, where a closing parenthesis is expected, but something else is found instead.