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+--- Thread: facing problem with running interactive shell using paramiko (/thread-641.html)
facing problem with running interactive shell using paramiko - saswatidas437 - Oct-26-2016
I have written below code to run 3 command in remote server interactively
But when i checked 3rd command never executed and code stuck here is my code
def execute():
ssh = paramiko.SSHClient()
ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
ssh.connect('ipaddress',username='user', password='pw')
chan=ssh.invoke_shell() # start the shell before sending commands
chan.send('cd /path to folder/test')
chan.send('\n')
time.sleep(3)
chan.send("ls -l")
chan.send('\n')
buff=''
while not buff.endswith(">"):
resp = chan.recv(9999)
# code stuck here after 'path to folder/test >' comes in shell prompt
buff+=resp
print resp
print "test"
chan.send("ls -lh")
chan.send('\n')
time.sleep(5)
buff=''
while not buff.endswith(">"):
resp = chan.recv(9999)
buff+=resp
print resp
if __name__ == "__main__":
execute() When i ran i got output of ls -l but ls -lh never executed my code stuck in first while loop. Anyone please help to resolve my issue
RE: facing problem with running interactive shell using paramiko - Larz60+ - Oct-26-2016
Put a couple of print statements to print resp and buff.
In addition, put the while loop code in a try except loop that way you'll capture any errors.
If you can set a timeout, that may help, as it may give you a timeout message
(hopefully something more verbose than ... timed out)