Modifying / extracting multiple list items simultaneously using variable from range - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: Modifying / extracting multiple list items simultaneously using variable from range (/thread-6762.html) |
Modifying / extracting multiple list items simultaneously using variable from range - ehammarlund - Dec-06-2017 I am a beginner(**) trying to figure out how to put multiple items in/out of lists using variables. To demonstrate, I'm trying to make a prime sieve. [u]My comments/questions bolded below. highnum=1000000 #the number you’re checking to, here it's a million, could be anything erik=list(range(1,highnum) #create a list to sieve it def sieve(x): erik[(2x)::x]=False #I CAN’T FIGURE OUT HOW TO ASSIGN MULTIPLE LIST VALUES AT THE SAME TIME. CAN IT BE DONE? It doesn’t seem to want to accept a variable in the list definition so perhaps not…? I ALSO TRIED: erik.insert[(2x)::x]=FalseTHAT DID NOT WORK EITHER. SIGH. IF I CAN GET IT TO WORK, THEN IN THEORY I CAN DO THIS: for y in range (1,((highnum/2)+1)): sieve(y) sieveoutput=(Erik[] where erik!= False)#WILL THIS WORK/WHY WON’T THIS WORK? HELP! OR DO I NEED TO DO IT LIKE THIS? For z in range(1,highnum): iferik(z) != False: sieveoutput.append erik[z]Sorry about the very low-level questions;I literally started to learn Python three days ago. Thanks in advance for any pointers. RE: Modifying / extracting multiple list items simultaneously using variable from range - hshivaraj - Dec-06-2017 def sieve(x): erik[(2x)::x]=FalseIm not sure what your trying to do here. In fact what your trying to do there is syntactically wrong! Quote:I CAN’T FIGURE OUT HOW TO ASSIGN MULTIPLE LIST VALUES AT THE SAME TIME. CAN IT BE DONE? It doesn’t seem to want to accept a variable in the list definition so perhaps not…? Did you mean something like this? >>> a = list(range(100)) >>> >>> a = [False] * 100 >>> >>> a [False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False, False] RE: Modifying / extracting multiple list items simultaneously using variable from range - ehammarlund - Dec-06-2017 Thanks! I am trying to begin at index value= 2x (whatever x is as per the range loop) and replace the number in the list with "False" throughout the whole list, every X steps. As an example for x=3, the list 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20 would become(new changes underlined) 1,2,3,4,5,False,7,8,False,10,11,False,13,14,False,16,17,False,19,20 and if I then ran that same function for x=5 it would become (new changes underlined): 1,2,3,4,5,False,7,8,False,False,11,False,13,14,False,16,17,False,19,False (yes, I know that my actual code includes x=2 and x=4, but I left them out because they make it hard to illustrate what I'm doing.) Eventually the list would only contain "False" and primes. I can then either output a list of primes if I want them or can leave the list as-is for a very quick way to check the primacy of a number. If I succeed, I'll choose which output to use later on. I don't know yet whether there's a material speed difference in a) testing "is list[index]==False" versus b) testing "is [item] contained in list" RE: Modifying / extracting multiple list items simultaneously using variable from range - nilamo - Dec-06-2017 Quote: As an example for x=3, the list You can assign to a list slice, but only using another list of the same length of the slice you're replacing. So for this, it'd look something like: >>> items = list(range(21)) >>> items [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20] >>> replace = 3 >>> items[::replace] [0, 3, 6, 9, 12, 15, 18] >>> slice = items[::replace] >>> items[::replace] = [False for _ in range(len(slice))] >>> items [False, 1, 2, False, 4, 5, False, 7, 8, False, 10, 11, False, 13, 14, False, 16, 17, False, 19, 20] RE: Modifying / extracting multiple list items simultaneously using variable from range - ehammarlund - Dec-06-2017 aaaaaah. That explains so much--thanks a ton!! |