Product of maximum in first array and minimum in second - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: Product of maximum in first array and minimum in second (/thread-7650.html) |
Product of maximum in first array and minimum in second - Thethispointer - Jan-19-2018 So I am practicing the following Quote:Given two arrays of size N1 and N2 respectively, the task is to calculate the product of max element of first array and min element of second array. https://practice.geeksforgeeks.org/problems/product-of-maximum-in-first-array-and-minimum-in-second/0 I was writing this program and got hung up on an error... Quote:Traceback (most recent call last): #Given two arrays of size N1 and N2 respectively, the task is to #calculate the product of max element of first array and min #element of second array. # # A = [1, 50, 2, 7, 3, 8] B = [1, 50, 2, 7, 3, 8, 75, 77, 0] listALength = len(A) listBLength = len(B) #These print functions were used to test the len function on arrays during #this study session. They're now commented out to make them inactive. #print(listALength) #print(listBLength) #Take the length of the array - 1 to increment the list via a loop x = A[0] for i in A: y = A[i] if y > x: x = y print(x)Please help me! Thank you! RE: Product of maximum in first array and minimum in second - j.crater - Jan-19-2018 The "i" in your line for i in A: is not an index as you have probably expected. It is the element of A accessed in a single iteration of for loop. Try this:for i in A: print(i)For getting indexes you can use enumerate . Here is an example:my_list = ['one', 'two', 'three'] for i, number in enumerate(my_list): print(i, number)As a side note, you may want to get yourself familiar with min() and max() Python functions. Also, array in Python is called list, if you care about avoiding "foul language" ;P RE: Product of maximum in first array and minimum in second - Thethispointer - Jan-19-2018 Awesome, awesome, awesome! Thank you! Here is the functional code, now let's add min() and max()... or maybe tomorrow morning as it's getting pretty late here in the Midwest. #Given two Lists of size N1 and N2 respectively, the task is to #calculate the product of max element of first List and min #element of second List. A = [1, 50, 2, 7, 3, 8] B = [1, 50, 2, 7, 3, 8, 75, 77, 0] listALength = len(A) listBLength = len(B) x = A[0] for i, number in enumerate(A): y = A[i] if y > x: x = y print(x) Okay, with min() and max(). #Given two Lists of size N1 and N2 respectively, the task is to #calculate the product of max element of first List and min #element of second List. A = [1, 50, 2, 7, 3, 8] B = [1, 50, 2, 7, 3, 8, 75, 77, 0] print(min(B) + max(A)) RE: Product of maximum in first array and minimum in second - j.crater - Jan-19-2018 Code looks much nicer/shorter. Except the task ultimately requires a product, not sum of those elements, if I understood right =) RE: Product of maximum in first array and minimum in second - Thethispointer - Jan-19-2018 (Jan-19-2018, 07:08 AM)j.crater Wrote: Code looks much nicer/shorter. Except the task ultimately requires a product, not sum of those elements, if I understood right =) Yes indeed you are correct! I guess I should read more carefully! Thank you again for your help, I will definitely post some more code onto the forum when I find another issue I am hung up on! RE: Product of maximum in first array and minimum in second - j.crater - Jan-19-2018 No problem, we are glad to help! =) Beside posting when you hit an obstacle, feel free to also post in Completed Scripts/Snippets subforum, if you would like to share your working code and get some feedback for improvement ;) RE: Product of maximum in first array and minimum in second - Larz60+ - Jan-19-2018 Quote:Given two arrays of size N1 and N2 respectively, the task is to calculate the product of max element of first array and min element of second array.>>> A = [1, 50, 2, 7, 3, 8] >>> B = [1, 50, 2, 7, 3, 8, 75, 77, 0] >>> max(A) * min(B) 0 >>> RE: Product of maximum in first array and minimum in second - j.crater - Jan-19-2018 I guess that is alright. Example on the link Thethispointer provided even has a negative number in B list. So result can end up negative as well. RE: Product of maximum in first array and minimum in second - Larz60+ - Jan-19-2018 >>> B = [1, 50, 2, 7, 3, 8, 75, 77, 0, -5] >>> max(A) * min(B) -250 >>> RE: Product of maximum in first array and minimum in second - Thethispointer - Jan-19-2018 (Jan-19-2018, 04:44 PM)j.crater Wrote: No problem, we are glad to help! =)Yeah, I will do this! (Jan-19-2018, 05:23 PM)Larz60+ Wrote:Thank you! This is accurateQuote:Given two arrays of size N1 and N2 respectively, the task is to calculate the product of max element of first array and min element of second array.>>> A = [1, 50, 2, 7, 3, 8] |