loop until user enters no - Printable Version +- Python Forum (https://python-forum.io) +-- Forum: Python Coding (https://python-forum.io/forum-7.html) +--- Forum: General Coding Help (https://python-forum.io/forum-8.html) +--- Thread: loop until user enters no (/thread-7710.html) |
loop until user enters no - JohnnyFobby - Jan-22-2018 I started learning python 3 days ago and needed some help on my code... #Basic calculator #First python calculator #How to improve this??? name = str(input("Hello please enter in your name: ")) print("Nice meeting you " + name) print("This is a very basic calculator that i've made. Hope you enjoy!") def calculator(): choose = str(input("ADDITION(a), MULTIPLICATION(m), SUBTRACTION(s), DIVISION(d) ")) if choose == 'a': number1 = int(input("Choose your first number: ")) number2 = int(input("Choose your second number: ")) print(number1 + number2) elif choose == 's': number1 = int(input("Choose your first number: ")) number2 = int(input("Choose your second number: ")) print(number1 - number2) elif choose == 'm': number1 = int(input("Choose your first number: ")) number2 = int(input("Choose your second number: ")) print(number1 * number2) elif choose == 'd': number1 = int(input("Choose your first number: ")) number2 = int(input("Choose your second number: ")) print(number1 / number2) calculator() go_again = str(input("Would you like to go again? Y/N ")) if go_again == 'y': calculator() #How to loop this??? elif go_again == 'n': print("Goodbye...") exit()i want to loop the "go_again" var to where it keeps running until the user enters "no", because right now it only runs once. My guess is that it needs a while loop, but how would i do that? RE: Help - j.crater - Jan-22-2018 while True: calculator() go_again = str(input("Would you like to go again? Y/N ")) if go_again == 'y': continue elif go_again == 'n': print("Goodbye...") break RE: Help - JohnnyFobby - Jan-22-2018 (Jan-22-2018, 06:53 AM)j.crater Wrote:while True: calculator() go_again = str(input("Would you like to go again? Y/N ")) if go_again == 'y': continue elif go_again == 'n': print("Goodbye...") break Thanks bud! RE: Help - j.crater - Jan-22-2018 You are welcome, and I believe you understand how it works, since it is quite simple code. By the way, you don't need str before input, because input will return string in any case. RE: Help - JohnnyFobby - Jan-22-2018 (Jan-22-2018, 07:23 AM)j.crater Wrote: You are welcome, and I believe you understand how it works, since it is quite simple code. yes i understand it. Also thanks for the tip! (Jan-22-2018, 07:23 AM)j.crater Wrote: You are welcome, and I believe you understand how it works, since it is quite simple code. Do you have any other tips for me? |